Question

我正在使用：

from collections import Counter
wordlist = open('mybook.txt','r').read().split()
c = Counter(wordlist)
print c

# result :
# Counter({'the': 9530, 'to': 5004, 'a': 4203, 'and': 4202, 'was': 4197, 'of': 3912, 'I': 2852, 'that': 2574, ... })

打印一本书的所有单词，按频率排序。

如何在.txt输出文件中写入此结果？

g = open('wordfreq.txt','w')
g.write(c)   # here it fails

以下是所需的输出wordfreq.txt：

  ，9530   到，5004
  a，5004
  并且，4203
  是，4197
  ...

Answer 1

如果你想以排序的方式写它，你可以这样做。

from collections import Counter
wordlist = open('so.py', 'r').read().split()
word_counts = Counter(wordlist)

write_file = open('wordfreq.txt', 'w')
for w, c in sorted(word_counts.iteritems(), key=lambda x: x[1], reverse=True):
    write_file.write('{w}, {c}\n'.format(w=w, c=c))

Answer 2

我认为这可能是您需要的帮助：如何以您请求的格式打印字典。前四行是您的原始代码。

{{1}}

Answer 3

我认为这可以更简单地完成。我还使用了一个上下文管理器（with）来自动关闭文件

from collections import Counter

with open('mybook.txt', 'r') as mybook:
    wordcounts = Counter(mybook.read().split())

with open('wordfreq.txt', 'w') as write_file:
    for item in word_counts.most_common():
        print('{}, {}'.format(*item), file=write_file)

如果文件特别大，您可以使用

一次性将其全部读入内存

    wordcounts = Counter(x for line in mybook for x in line.split())

按书本排序的单词（.txt文件）

3 个答案: