如何从我的表中选择不同的列?

时间:2015-11-05 06:34:58

标签: sql sql-server group-by distinct

我有两张桌子可供使用。第一个表#CustomerList我用值手动初始化。然后我创建了第二个表#CustomerListWithRank_Id,该表基于第一个表#CustomerList

第一个表和第二个表之间的唯一不同之处在于,第二个表#CustomerListWithRank_Id有一个列,它为每行提供了当我遍历该表时我在SQL代码中进一步使用的rownumber

所以我遇到的问题是我只想用[FileName]列中的唯一值来初始化#CustomerListWithRank_Id,我该怎么做?

SELECT '3004' Customer_No,'831001' DDD_Reference_No,'varer831.csv' [FileName]
INTO #CustomerList -- DROP TABLE #CustomerList
UNION ALL SELECT '3002' Customer_No,'199001' DDD_Reference_No,'varer199.csv' [FileName]
UNION ALL SELECT '3003' Customer_No,'199002' DDD_Reference_No,'varer199.csv' [FileName]

-

SELECT *, ROW_NUMBER() OVER (ORDER BY Customer_No) AS 'Rank_Id'
INTO #CustomerListWithRank_Id --DROP TABLE #CUstomerListWithRank_ID
FROM #CustomerList

如果我在上面的查询中使用GROUP BY [FileName],我会收到此错误:

Msg 8120, Level 16, State 1, Line 1
Column '#CustomerList.Customer_No' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.

2 个答案:

答案 0 :(得分:1)

这是你需要的吗?

select *, ROW_NUMBER() OVER (ORDER BY Customer_No) AS 'Rank_Id'
INTO #CustomerListWithRank_Id 
from
(
    SELECT max(Customer_No) Customer_No, max(DDD_Reference_No) DDD_Reference_No, FileName
    FROM #CustomerList
    group by FileName
) t

答案 1 :(得分:0)

这就是你需要的

SELECT * INTO #CustomerListWithRank_Id From
(SELECT *, ROW_NUMBER() OVER (PARTITION BY FileName Order by Customer_No)  AS RowNum FROM CustomerList)
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