Question

SELECT `user_appoint`.`ApptDateTime` AS ApptDate,`user_appoint`.`id` AS appt_id,        `user_appoint`.`ref_no` AS ref_no, `user_appoint`.`status_id` AS status_id,  `user_det`.`pass_no`, `user_det`.`f_name` AS fname, `user_appoint`.`date`, `user_det`.`l_name` AS lname, `user_det`.`dob` AS dob, `tbl_pi`.`Pi`, `tbl_vesselmaster`.`id` AS Vid, `user_det`.`id` AS user_id, `user_appoint`.`dr_comments` AS Remarks
FROM (`user_det`)
JOIN `user_appoint` ON `user_appoint`.`u_id` = `user_det`.`id`
LEFT JOIN `tbl_pi` ON `user_appoint`.`id` = `tbl_pi`.`ApptId`
JOIN `tbl_rank` ON `user_appoint`.`rank` = `tbl_rank`.`rank_id`
JOIN `tbl_typeofmedical` ON `tbl_typeofmedical`.`Id`=`user_appoint`.`purpose`
JOIN `tbl_vesselmaster` ON `tbl_vesselmaster`.`id` = `user_appoint`.`vessel`
JOIN `tbl_clinic_list` ON `tbl_clinic_list`.`Id` = `user_appoint`.`ClinicId`
JOIN `pate_status` ON `pate_status`.`id`=`user_appoint`.`status_id`
LEFT JOIN `tbl_doctorlist` ON `tbl_doctorlist`.`id`=`user_appoint`.`DrId`
LEFT JOIN `tbl_fleetvessel` ON `tbl_fleetvessel`.`VesselId` = `user_appoint`.`vessel`
WHERE `user_appoint`.`void` =  0
AND `user_appoint`.`comp_id` =  '123'
AND `user_det`.`3cc_id`  LIKE '%%'
AND `user_appoint`.`ref_no`  LIKE '%%'
AND  `user_appoint`.`DrId`  LIKE '%%'
AND  `tbl_fleetvessel`.`FleetId`  LIKE '%%'
AND  `ApptDateTime`  LIKE '%%'
ORDER BY `user_appoint`.`ApptDateTime` DESC
LIMIT 15

这是返回以下结果的myquery

ApptDate                      f_name       l_name  
--------------               -------      -------
13-11-2015                    xyz           pqr
06-11-2015                    abc           uio
04-11-2015                    qwe           jkl

我希望桌子显示今天的结果，然后是未来的结果，然后是其他结果。

Answer 1

只需更改查询的order by子句：

ORDER BY DATE_FORMAT(`user_appoint`.`ApptDateTime`, '%d-%m-%Y') = DATE_FORMAT(NOW(), '%d-%m-%Y') DESC, `user_appoint`.`ApptDateTime` > NOW() DESC, `user_appoint`.`ApptDateTime` DESC

这样，第一个结果是日期与今天匹配的结果，下一个结果是日期大于今天（=未来）的结果，然后其余结果按降序排列。

Answer 2

只需在您的ORDER BY中使用CASE WHEN条件：

ORDER BY
  CASE
    WHEN DATE(user_appoint.ApptDateTime) = CURDATE() THEN 1
    WHEN DATE(user_appoint.ApptDateTime) > CURDATE() THEN 2
    ELSE 3
  END

Mysql在未来日期结果之前返回今天的结果

2 个答案: