从字符串中提取数据

时间:2015-11-07 08:00:29

标签: php regex

$str= 'We have new Call Request: Reference = 55823014, Name = Amal, Mobile = 111111'

如何从字符串中提取此部分,如:

reference |  55823014
Name      |  Amal
Mobile    |  1111111

3 个答案:

答案 0 :(得分:2)

使用正则表达式提取

$str= 'We have new Call Request: Reference = 55823014, Name = Amal, Mobile = 111111';

preg_match('/Reference =(.*?), Name =(.*?), Mobile =(.*)/', $str, $m);

print_r($m);
//if you want to display an item at a time

echo "Reference = ".$m[1].PHP_EOL;
echo "Name = ".$m[2].PHP_EOL;
echo "Mobile = ".$m[3].PHP_EOL;

这会给你

Array
(
    [0] => Reference = 55823014, Name = Amal, Mobile = 111111
    [1] =>  55823014
    [2] =>  Amal
    [3] =>  111111
)
Reference =  55823014
Name =  Amal
Mobile =  111111

<强> Demo

答案 1 :(得分:1)

首先删除文字&#39;我们有新的通话请求:&#39;从字符串。然后,您将获得包含键值对的主字符串。从那里,您可以用逗号将其分解为一个标记数组,其中每个标记包含一个键值对。然后你遍历标记并通过用等于&#39; =&#39;爆炸它来分离出键值。标志。这是代码:

<?php
$str = 'We have new Call Request: Reference = 55823014, Name = Amal, Mobile = 111111';
$str = substr($str, strpos($str, ':') + 1);
$arr = explode(',', $str);
$data = array();
foreach ($arr as $item) {
    $tokens = explode('=', $item);
    $key = trim($tokens[0]);
    $val = trim($tokens[1]);
    $data[$key] = $val;
}
var_dump($data);

答案 2 :(得分:0)

好的作为快速方法,这应该有效:

$str= 'We have new Call Request: Reference = 55823014, 
       Name = Amal, Mobile = 111111';
$str = strchr($str, "Reference");
$str = explode(',', $str);

foreach ($str as $item) {
$tokens = explode('=', $item);
$key = trim($tokens[0]);
$val = trim($tokens[1]);
echo $key . " | " . $val . PHP_EOL;
}

输出:

Reference | 55823014
Name | Amal
Mobile | 111111
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