迅速和放大器; parse.com：将String转换为AnyObject？

Question

更新解析表中的值我编写了这行代码：

                  object["score"] = self.selectedScore

但它给了我错误：

cannot assign value of type 'Int' to a value of type 'AnyObject?!'

所以我考虑将self.selectedScore转换为类型AnyObject?!

这就是我做到的：

if let var castScore = self.selectedScore as! AnyObject?
{

                      object["score"] = castScore
}

但仍出现另一个错误，指出castScore的类型为AnyObject? object["score"]类型为AnyObject?!

有没有办法让castScore成为AnyObject?!类型？

表格跟踪：

table

CODE：

 //test
            var taskQuery = PFQuery(className: "Track")
            //run query
            taskQuery.findObjectsInBackgroundWithBlock({
                (success:[AnyObject]?, error: NSError?) -> Void in
                if let objects = success {
                    for object in objects  {




                        var name  = sucess["taskName"]
                        var score  = sucess["score"]

                        var unwrappedName = ""
                        var unwrappedScore = ""

                        if let name = name {
                            unwrappedName = "\(name!)"
                        }

                        if let score = score {
                            unwrappedScore = "\(score!)"
                        }


                        if unwrappedName == Track {


                                object["score"] = self.selectedScore //#ERROR

                            sucess.saveInBackgroundWithBlock { (success: Bool, error: NSError?) -> Void in
                                println("Object has been saved.")
                            }



                        }
                        //trackMgr.addTrack(unwrappedName, score: unwrappedScore.toInt()!, view: false)
                    }



                }


            })

            //test

Answer 1

我认为当你使用它时，你应该打开success!["score"]。

 if let _ = sucess["score"] {

    var score = success!["score"]
}

Answer 2

删除该行末尾的问号。

if let var castScore = self.selectedScore as! AnyObject
{
   object["score"] = castScore
}