如何将exp转换为java exp

Question

我有一份作业

我不知道如何将表达式转换为Java。 有时我必须加括号，它会改变解决方案， 我不确定，如果我的代码是对的。

我写了这段代码：

double number1 = 10;
double number2 = 20;
double number3 = 30;

int sum = (int) (number1 + number2 + number3);
double average = sum / 3;

int product = (int) (number1 * number2 * number3);
double exp = (10.5 / number3) + (5 + number1 * number2) / (number3 - number1) * 12;

System.out.println("The sum is: " + sum);
System.out.println("The product is: " + product);
System.out.println("The average is: " + average);
System.out.println("The expression result is: " + exp);

Answer 1

int sum = (int) (number1 + number2 + number3);

将sum作为double ..不需要将其转换为int。您将失去精度。

int product = (int) (number1 * number2 * number3);

同样适用于此。

休息看起来不错。

Answer 2

我只看到一个问题：

double average = sum / 3;

是整数除法，对于某些输入会失败（它仍然适用于您的数字）但它应该是这样的：

double average = sum / 3.0;

您可以将sum的类型更改为double

Answer 3

每个人都帮助我。

我解决了这个问题

package home1;

public class Arithmetic {

    public static void main(String[] args) {

        int number1 = 10;
        int number2 = 15;
        int number3 = 35;

        int sum =  (number1 + number2 + number3);
        double average = sum / 3.0;

        int product = (number1 * number2 * number3);
        double exp = (10.5 / number3) + (5 + number1 * number2) / (number3 - number1) * 12;

        System.out.println("The sum is: " + sum);
        System.out.println("The product is: " + product);
        System.out.println("The average is: " + average);
        System.out.println("The expression result is: " + exp);
    }
}