Question

我在Angular JS中创建一个站点的一部分，显示来自服务器的一些报告数据。由于我在表格中显示它，我需要的格式可以很容易地用ng-repeat显示。

因此，我需要将服务器中的JSON数据转换为JavaScript对象。我已经获得了我想要的数据的目标格式，这个对象使用了“捐赠程序”的名称。作为键，作为它们的值，每个对应一个月的对象数组。每个对象都有月份名称，在网站上注册的人数，捐赠人数以及捐赠总额。

我很难通过JSON迭代并将其转换为该格式。有人可以看看吗？我已经包含了我获得的服务器数据以及我尝试格式化它的方式。感谢。

服务器数据：

$scope.serverData = {
"registration_by_month": [
    {
        "month": "November 2015",
        "registration_program": "Donor Program 1",
        "count": 3
    },
    {
        "month": "November 2015",
        "registration_program": "Donor Program 2",
        "count": 4
    },
    {
        "month": "December 2015",
        "registration_program": "Donor Program 1",
        "count": 5
    },
    {
        "month": "December 2015",
        "registration_program": "Donor Program 2",
        "count": 6
    }
],

"donors_by_month": [
    {
        "month": "November 2015",
        "registration_program": "Donor Program 1",
        "count": 2
    },
    {
        "month": "November 2015",
        "registration_program": "Donor Program 2",
        "count": 1
    },
    {
        "month": "December 2015",
        "registration_program": "Donor Program 1",
        "count": 2
    },
    {
        "month": "December 2015",
        "registration_program": "Donor Program 2",
        "count": 1
    }
],

"donated_amount_by_month": [
    {
        "month": "November 2015",
        "registration_program": "Donor Program 1",
        "amount": 100
    },
    {
        "month": "November 2015",
        "registration_program": "Donor Program 2",
        "amount": 200
    },
    {
        "month": "December 2015",
        "registration_program": "Donor Program 1",
        "amount": 50
    },
    {
        "month": "December 2015",
        "registration_program": "Donor Program 2",
        "amount": 40
    }
]

};

目标数据：

$scope.targetData = {
"Donor Program 1": [{month:"November 2015", registered:3, donors:2, donated_amount:100},{month:"December 2015", registered:4, donors:1, donated_amount:200}],
"Donor Program 2:": [{month:"November 2015", registered:5, donors:2, donated_amount:50},{month:"December 2015",registered:6, donors:1, donated_amount:40}]

};

Answer 1

试试这个

 var temp = {};
 data.registration_by_month.forEach(function (x) {
     if (!temp[x.registration_program]) {
         temp[x.registration_program] = [];
     }
     var dtmon = data.donors_by_month.find(function (y) {
         return y.registration_program == x.registration_program;
     });
     var dnmon = data.donated_amount_by_month.find(function (y) {
         return y.registration_program == x.registration_program;
     });
     temp[x.registration_program].push({
             month: x.month,
             registered: x.count,
             donors: dtmon ? dtmon.count : 0,
             donated_amount: dnmon ? dnmon.amount : 0
     });

 });
console.log(temp);

<强> JSFIDDLE

编辑

IE和Opera不支持

.find。

您可以尝试 .filter

喜欢这个

 var temp = {};
 data.registration_by_month.forEach(function (x) {
     if (!temp[x.registration_program]) {
         temp[x.registration_program] = [];
     }
     var dtmon = data.donors_by_month.filter(function (y) {
         return y.registration_program == x.registration_program;
     });
     var dnmon = data.donated_amount_by_month.filter(function (y) {
         return y.registration_program == x.registration_program;
     });
     temp[x.registration_program].push({
             month: x.month,
             registered: x.count,
             donors: dtmon.length > 0 ? dtmon[0].count : 0,
             donated_amount: dnmon.length > 0 ? dnmon[0].amount : 0
     });

 });

<强> JSFIDDLE

无法从服务器格式化此JSON数据

1 个答案: