Question

这是我的数组输出：

array:2 [
  0 => array:1 [
    "medium " => " 1"
  ]
  1 => array:1 [
    " small " => " 2"
  ]
]

我的解决方案

$sumVariant = array();
            foreach ($data as $key => $value) {
                        foreach ($value as $k => $v) {
                                    //dd(trim($v));
                            $sumVariant += trim($v);
                        }
            }
dd($sumVariant);

如何计算返回3的medium和small的总数？谢谢！

Answer 1

我在你的问题中写下你的代码。并进行如下修改。它给你正确的答案。

<?php
$data =array(0=>array("medium "=>" 1"),1=>array(" small "=>" 2"));

$sumVariant=0;
foreach ($data as $key => $value) {
            foreach ($value as $k => $v) {
                        //dd(trim($v));
                $sumVariant += trim($v);
            }
}
echo $sumVariant;?>

Answer 2

<?php
$total = 0;
foreach ($array as $inputArray) {
    if (array_key_exists ("medium", $array)) $total += $array["medium"] ;   
    if (array_key_exists ("small",  $array)) $total += $array["small"]  ;
}

Answer 3

使用array_walk_recurive

$array_total = 0;
$arr = array(array('small'=>2), array('medium'=>1));
array_walk_recursive($arr, function($value, $key){
    global $array_total;
 $array_total += $value;
});
    echo $array_total; // output 3

Answer 4

 $data =array(0=>array("medium "=>" 1"),1=>array(" small "=>" 2"));



 foreach ($data as $array_single) {
                           $sum_value += array_sum($array_single);

                }
echo $sum_value;

array_sum（）返回整数之和表示为字符串或int

examle :: -

<?php
$a=array(' 5',15,25,'ajj');
echo array_sum($a);
?>

O / P :: - 45

Php数组计算键值对的总值

4 个答案: