错误:没有匹配函数调用'TNode <student> :: TNode <const student&)'=“”

时间:2015-11-19 19:27:13

标签: c++ linked-list binary-tree nodes

=“”

我有这个每当我想在C ++上使用模板在二叉树上添加元素并且我在修复它时遇到困难,

所以这里的代码是Tree.c文件:

template <class Whatever>
ostream & operator << (ostream &, const TNode<Whatever> &);

template <class Whatever>
struct TNode {
    long balance;
    Whatever data;
    long height;
    TNode<Whatever>* left;
    long & occupancy;
    TNode<Whatever>* right;
    unsigned long & tree_count;

    TNode (const Whatever & element, Tree<Whatever> & theTree)
           :balance (0), data (element), height(0), left(0), 
           occupancy(theTree.occupancy), right(0),
           tree_count (theTree.tree_count) {
                occupancy++;
    }

    TNode (const Whatever & element, TNode<Whatever> & parentTNode)
     : balance(0), data (element), height (0), left (0),
            occupancy(parentTNode.occupancy), right (0),
            tree_count (parentTNode.tree_count) {
              occupancy++;
    }


template <class Whatever>
unsigned long Tree<Whatever> :: Insert (const Whatever & element) {
    //check to see if the tree is empty
    if(root == NULL)
    {  
         root = new TNode<Whatever>(element); //this is keep on giving me the no 
                                              //matching function error
         return TRUE;
    }

    return FALSE;
}

这是我的Tree.h文件:

template <class Whatever>
struct TNode;

template <class Whatever>
class Tree {
    friend struct TNode<Whatever>;
    long occupancy;
    TNode<Whatever> * root;
    unsigned long tree_count;
    static int debug;
public:
    //here are my constructor and destructor

    unsigned long Insert (const Whatever &);

这是我的Driver.h文件:

class Student {
    friend ostream & operator << (ostream &, const Student &);
    char name[20];
    long studentnum;
public:
       //here are my constructor,copy constructor, and deconstructor

每当我尝试编译时,我都会收到错误消息,

Tree.c:在成员函数'long unsigned int Tree :: Insert(const Whatever&amp;)[with Whatever = Student]:

Tree.c:140:错误:没有匹配函数来调用'TNode :: TNode(const Student&amp;)'

Tree.c:48:注意:候选人是:TNode :: TNode(const Whatever&amp;,TNode&amp;)[与Whatever = Student]

Tree.c:40:注意:TNode :: TNode(const Whatever&amp;,Tree&amp;)[with Whatever = Student]

Tree.c:31:注意:TNode :: TNode(const TNode&amp;)

任何人都知道如何修复此错误??

1 个答案:

答案 0 :(得分:1)

你的两个TNode构造函数都有两个参数。你只传递了一个。

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