Question

我正在寻找一个替代连接的python。

我正在尝试获取当天每一秒的列表，并根据时间戳将数据加入到该列表中。到目前为止，我的是：

keys=('DRIP_ID','DESCR','OBJECT','TIMESTAMP','DRIP_R1','DRIP_R2','RT_DISP1','RT_DISP2','DAY','TIME')

键是列名

rawdata=[['242418',"242418 Rechts.BD242418: tot Oudkarspel -  - ${pijlop} N242  10 min - N508  14 min${pijlr}",'BD242418','20150701063825','N242','N508','10','14','20150701','063825'],
['242418',"242418 Rechts.BD242418: tot Oudkarspel -  - ${pijlop} N242  10 min - N508  14 min${pijlr}",'BD242418','20150701064327','N242','N508','10','14','20150701','064327'],
['242418',"242418 Rechts.BD242418: tot Oudkarspel -  - ${pijlop} N242  10 min - N508  14 min${pijlr}",'BD242418','20150701085717','N242','N508','10','14','20150701','085717'],
['242418',"242418 Rechts.BD242418: tot Oudkarspel -  - ${pijlop} N242  10 min - N508  14 min${pijlr}",'BD242418','20150701100116','N242','N508','10','14','20150701','100116'],
['242418',"242418 Rechts.BD242418: tot Oudkarspel -  - ${pijlop} N242  10 min - N508  14 min${pijlr}",'BD242418','20150701191611','N242','N508','10','14','20150701','191611'],
['242418',"242418 Rechts.BD242418: tot Oudkarspel -  - ${pijlop} N242  10 min - N508  14 min${pijlr}",'BD242418','20150701213616','N242','N508','10','14','20150701','213616']]

rawdata来自软件

sec = ['00','01','02','03','04','05','06','07','08','09','10','11','12','13','14','15','16','17','18','19','20','21','22','23','24','25','26','27','28','29','30','31','32','33','34','35','36','37','38','39','40','41','42','43','44','45','46','47','48','49','50','51','52','53','54','55','56','57','58','59']
mm = sec
hh = ['00','01','02','03','04','05','06','07','08','09','10','11','12','13','14','15','16','17','18','19','20','21','22','23']
timestamp=()
time = []
dictData = []

# Dictionary with all seconds (HHMMSS) in 1 day
for ih, uur in enumerate(hh):
    if ih < 24:
          for im, minutes in enumerate(mm):
              if im < 60:
                  for isec, secs in enumerate(sec):
                      if isec < 60:
                        timestamp = str(uur)+str(minutes)+str(secs)
                        timeDict = dict()
                        timeDict['DRIP_ID']=""
                        timeDict['DESCR']=""
                        timeDict['OBJECT']=""
                        timeDict['TIMESTAMP']=""
                        timeDict['DRIP_R1']=""
                        timeDict['DRIP_R2']=""
                        timeDict['RT_DISP1']=""
                        timeDict['RT_DISP2']=""
                        timeDict['DAY']=""
                        timeDict['TIME']=timestamp
                        time.append(timeDict)

在这里，我在一天内完成了所有秒数并给了他们相同的键，以便于匹配

# Turn raw data into dictionary                        
for row in rawdata:
    dictionary = dict(zip(keys, row))
    dictData.append(dictionary)

然后我把rawdata转换成dict

#Join, sort off
compleet=()
for t in time:
    t.update(dictData)
    compleet.append(t)

print len(compleet)
print compleet[1]

然而，当我运行它时，我收到错误：

ValueError: dictionary update sequence element #0 has length 10; 2 is required

这让我相信我一次只能更新key：value对，但我不确定这是否正确。

此外：这是一个1：1的加入。 1个时间戳只能有1个测量值。不是每天都有一个测量。 “加入”将在“时间”

Answer 1

文档说：

dict.update = update（...）

D.update（[E，] ** F） - ＆gt;没有。从dict / iterable E和F更新D.

如果E存在且具有.keys（）方法，那么：对于E中的k：D [k] = E [k]

如果E存在且缺少.keys（）方法，那么：对于k，v在E中：D [k]   = v

在任何一种情况下，接着是：对于F中的k：D [k] = F [k]

由于dictData是一个列表并且没有keys()方法，for k, v in dictData: t[k] = v方法会运行update并导致异常。

实际上我并不完全理解您的代码，因此我无法为此提供具体帮助。

如果您能解释代码（例如执行后的正确t变量），我想帮助您。

Answer 2

#Same result as a join, by iterating.
for iTime, t in enumerate(time):
    for iData, d in enumerate(dictData):
        if t['TIME'] == d['TIME']:
            t.update(d)

在意识到出了什么问题并且没有加入之后，这是最好的下一步。

python基于键的字典合并列表

2 个答案: