这是一款使用C ++创建的棋盘游戏。为了获胜，一名球员必须能够三次到达棋盘的末端。但问题在于，它是第一个进入棋盘游戏的球员，总是赢球。我有一个功能设置，所以模拟骰子使用随机数发生器。我该如何解决这个问题？
#include <iostream>
using namespace std;
#include <cstdlib>
#include <ctime>
#include <cmath>
#include <string>
#define SIZE 20 //EDITED: SIZE is Defined at 20 for the number of squares wanted for the board game. Makes is easier for change
//NOTE TO SELF: This is the revamped version. "EDITED" marks addition/change from 'assignment2_fixed.cpp
/**********************
* FUNCTION PROTOTYPES *
***********************/
void displayRules();
void action();
void firstRoll();
void showState();
int spinDie();
bool play();
bool winner();
int square[SIZE]; //For each square on the board, SIZE is Defined
const int loseTurn=1, switchPlace=2, goAgain=3, moveBack=4; //CONSTANT! Labels each action location for each square
int *location, *lastsq, *losTurn; //EDITED: Declared for dynamic allocation for location on board, last square of board, and lost turn
string *names; //EDITED: This is to hold the names of the players
int numPlayers = 0; //Holds the number of players
int turn; //EDITED: First players turn
/************
* FUNCTIONS *
*************/
void displayRules(){ //Displays the rules to the player once the game starts
cout << "Welcome to 3X" << endl;
cout << "The first player to go around the board three times wins!" <<endl;
cout << "The player with the lowest number goes first" << endl;
cout << "The players take turns until one player wins" << endl;
cout << "The players must move forward the number of spaces the die displays" << endl;
cout << "If the player lands on a square with an action, the player must perform that action, otherwise the next player goes" <<endl;
cout << endl << endl;
}
void action(){ //EDITED: This lists actions for each square
square[2] = goAgain;
square[4] = switchPlace;
square[6] = goAgain;
square[8] = loseTurn;
square[11] = goAgain;
square[14] = moveBack;
square[16] = switchPlace;
square[18] = loseTurn;
}
void firstRoll(){ //EDITED: Initializes for the first die roll
numPlayers = spinDie();
for(int i=0; i<numPlayers; i++)
location[i];
for(int i=0; i<numPlayers; i++)
lastsq[i];
for(int i=0; i<numPlayers; i++)
losTurn[i];
}
void showState(){
for(int i=0; i<numPlayers; i++){
cout << "Player " << names[i] << " is at location " << location[i] << endl;
}
for(int i=0; i<numPlayers; i++){
cout << names[i] << " lands on last space " << lastsq[i] << " times " << endl;
}
}
int spinDie(){ //For the dice. Number is generated randomly based on time
int x = rand()%6 +1 ;
cout<< " a "<< x<< " was rolled"<<endl;
return x;
}
bool play(){ //EDITED: Play function through squares
srand(time(0));
while(true){
if(losTurn[turn]){
losTurn[turn] = 0;//EDITED: Finds if player lost turn based on the value of 'turn'
turn = (turn) % numPlayers;
continue;
}
cout << "Turn: "<< names[turn] << endl;
int spot = spinDie(); //EDITED: Players spot on the board based on random number generator
cout << "Number on die : " << spot << endl;
location[turn] += spot;
if(location[turn] >= SIZE-1){
location[turn] -= SIZE;
lastsq[turn]++;
cout << names[turn] << " passes End!"<<endl;
if(winner())
return true;
}
switch(square[location[turn]]){
case goAgain:
cout<<"Action: Go again.\n";
showState();
break;
case loseTurn:
cout<<"Action: Lose turn.\n";
losTurn[turn] += 1;
break;
case switchPlace:
cout<<"Action: Switch places\n";
break;
case moveBack:
cout<<"Action: Move back 2 places.\n";
location[turn] -= 2;
break;
default:
cout<<"Action: None\n";
}
showState();
turn = (turn) % numPlayers;
}
return false;
}
bool winner(){ //Finds the winner who hits the end square three times
if(lastsq[turn] == 3){
cout<<"\n"<<names[turn]<<" WIN!\n";//Prints name of player with their turn
return true;
}
return false;
}
/***************
* MAIN PROGRAM *
****************/
int main(){
srand(time(0)); //Makes time based number in die random
displayRules(); //Diplays the rules first
cout << "Please type in the number of players between 1-6 : " << endl;
cin >> numPlayers;
while ((numPlayers < 1) || (numPlayers > 6)) //EDITED: Guard against any values outside of 1-6
{
cout << "ERROR: Enter a value from 1 - 6: ";
cin >> numPlayers;
}
names = new string[numPlayers]; //EDITED: Dynamically allocates array of string to hold names of players
location = new int[numPlayers]; //EDITED: Dynamically allocates array of int to hold locations of players
losTurn = new int[numPlayers]; //EDITED: Dynamically allocates array of int to hold lost turn of players
lastsq = new int[numPlayers]; //EDITED: Dynamically allocates array of int to hold count of each time player reach end square
for(int i=0; i<numPlayers; i++){
cout << "Enter name of player " << i+1 << " " << endl; //EDITED: To get name of each player starting with Player 1 (i+1)
cin >> names[i]; //EDITED: Gets names of players into the dynamically allocated strings
}
while(true){//EDITED: Continues the loop
if(play())//EDITED: If the "Play" function is true
break;//EDITED: Breaks once the winner is found
}
return 0;
}
答案 0 :(得分：0)
虽然你的问题很模糊，但我可以帮你一些帮助。首先，我将在骰子上显示随机因素的代码。
int spinDie(){ //For the dice. Number is generated randomly based on time
int x = rand()%6 +1 ;
cout<< " a "<< x<< " was rolled"<<endl;
return x;
此代码使编译器在整数范围内生成任意数字。然后将该随机数除以6，并使用余数运算符（％）查找余数。如果它是因子6，那么+1将添加到余数中，例如36.你的代码很好。问题在于它是基于时间的。电路板上的第一个可能每次都会得到相似或相同的数字，第二个也可能。这可以解释第一个总是赢的。我假设第一个每次都有类似或相同的卷，因为你对SPECIFIC问题缺乏解释。希望这有点帮助。