我有这个SQL查询:
$sql = "SELECT (SELECT SUM(total_pay) FROM workers) total,workers. * FROM workers WHERE projects_id = ".$id;
我想将数据显示在表格行中:
$stmt = mysqli_query($con, $sql) or die($sql."<br/><br/>".mysqli_errno($con));
<?php while($rows = mysqli_fetch_array($stmt)){ ?>
<form action="update_del.php" method="post">
<th>Payments</th>
<th>Date</th>
<th>Project</th>
<th width="25%">Delete</th>
<tr>
<?php while($rows = mysqli_fetch_array($stmt)){ ?>
<tr>
<td align="center"><?php echo $rows['total_pay']?></td>
<td align="center"><?php echo $rows['date_of_pay']?></td>
<td align="center"><?php echo $name['project_name'] ?></td>
<td align="center"><!--<input class="imgClass_insert" type="submit" name="submit1" value="" />-->
<input class="imgClass_dell" type="submit" onClick="return confirm('Are you sure you want to delete?')" name="delete_workers" value=""/>
</td>
</tr>
</tr>
<tr>
<td colspan="3">Total <?php echo $name['project_name']?></td>
<td><?php echo $rows['total'] ?></td>
</tr>
<?php } ?>
</table>
问题是,显示的每一行都会重复付款总和,那么如何在表格末尾只显示一次总和查询?应该将它放在为该总和指定的单个查询中吗?
答案 0 :(得分:1)
您可以从查询中删除library(data.table)#v1.9.6+
setDT(x)[order(time),Diff := shift(value, type= 'lead') - value ,
by = subject]
# subject time value Diff
#1: a 1 1.37095845 -0.7380958
#2: b 1 -0.56469817 0.9689665
#3: c 1 0.36312841 -0.4692529
#4: a 2 0.63286260 0.8786594
#5: b 2 0.40426832 -0.4989274
#6: c 2 -0.10612452 2.1245482
#7: a 3 1.51152200 NA
#8: b 3 -0.09465904 NA
#9: c 3 2.01842371 NA
并使用PHP进行计算,也可以只存储总数并在total
语句之外使用它。像
while
尽管你正在遍历所有结果,但最好将它从SQL中删除并计算出来。
<?php
$total = 0;
while($rows = mysqli_fetch_array($stmt)){
$total = $rows['total'];
?>
<tr>
<td align="center"><?php echo $rows['total_pay']; ?></td>
<td align="center"><?php echo $rows['date_of_pay']; ?></td>
<td align="center"><?php echo $name['project_name']; ?></td>
<td align="center">
<!--<input class="imgClass_insert" type="submit" name="submit1" value="" />-->
<input class="imgClass_dell" type="submit" onClick="return confirm('Are you sure you want to delete?')" name="delete_workers" value=""/>
</td>
</tr>
<?php } ?>
<tr>
<td colspan="3">Total <?php echo $name['project_name']; ?></td>
<td><?php echo $total; ?></td>
</tr>
</table>
$sql = "SELECT workers.* FROM workers WHERE projects_id = ".$id;
答案 1 :(得分:0)
如果我能正确理解您的问题,那么这可能会帮助您根据需要在最后一行中生成总和。
"SELECT total_pay, date_of_pay,project_name
FROM workers WHERE project_id=".$id."
UNION
SELECT 'ALL', SUM(total_pay)
FROM workers";