Question

我正在使用Spring Data REST来公开我的实体，我希望能够同时保存（创建和更新）父实体及其子实体。

以下是我的实体：

@Entity
@Table(name = "scenario")
@JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class, property = "id")
public class Scenario extends AbstractAuditableEntity {

    @Id
    // Sequence name must be preceded by schema name.
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "scenarioIdSeq")
    @SequenceGenerator(name = "scenarioIdSeq", sequenceName = "scenario_id_seq", allocationSize = 1)
    @Column(unique = true, nullable = false, columnDefinition = "SERIAL")
    private Long id;

    @Version
    // Used by JPA for optimistic locking
    protected int version;

    @OneToMany(mappedBy = "scenario")
    @LazyCollection(LazyCollectionOption.TRUE)
    private Set<Action> actions = new HashSet<Action>();
}

@Entity
@Table(name = "action")
@JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class, property = "id")
public class Action extends AbstractAuditableEntity {

    @Id
    // Sequence name must be preceded by schema name.
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "actionIdSeq")
    @SequenceGenerator(name = "actionIdSeq", sequenceName = "action_id_seq", allocationSize = 1)
    @Column(unique = true, nullable = false, columnDefinition = "SERIAL")
    private Long id;

    @Version
    // Used by JPA for optimistic locking
    protected int version;

    @RestResource(rel = "action_scenario")
    @ManyToOne(fetch = FetchType.EAGER)
    @JoinColumn(name = "scenario_id", columnDefinition = "BIGINT", nullable = false)
    private Scenario scenario;

    @JsonIgnore
    @OneToMany(mappedBy = "action")
    @LazyCollection(LazyCollectionOption.TRUE)
    private Set<ActionParameter> parameters = new HashSet<ActionParameter>();
}

@Entity
@Table(name = "action_parameter")
@JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class, property = "id")
public class ActionParameter extends AbstractAuditableEntity {

    @Id
    // Sequence name must be preceded by schema name.
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "actionParamIdSeq")
    @SequenceGenerator(name = "actionParamIdSeq", sequenceName = "action_parameter_id_seq", allocationSize = 1)
    @Column(unique = true, nullable = false, columnDefinition = "SERIAL")
    private Long id;

    @Version
    // Used by JPA for optimistic locking
    protected int version;

    @RestResource(rel = "parameter_action")
    @ManyToOne(fetch = FetchType.EAGER)
    @JoinColumn(name = "action_id", columnDefinition = "BIGINT", nullable = false)
    private Action action;
}

所以我希望能够同时（在同一个交易中）保存（创建和更新）整个场景及其动作和动作参数。

使用Spring Data REST实现这一目标的最佳方法是什么？

更新1：

我已经尝试按照建议使用cascade属性，但现在我收到了这个错误：

无法写入内容：检测到多条关联链接关系类型！消除关联歧义 @ org.springframework.data.rest.core.annotation.RestResource（路径=，出口= TRUE， description=@org.springframework.data.rest.core.annotation.Description（值=），相对= action_scenario）

每个关系都已使用@RestResource（rel =“xxx”）注释，所以我不明白为什么我会收到此错误？！

我错过了什么吗？

Answer 1

您必须在cascade注释中使用@OneToMany属性：

I.e。：

@OneToMany(mappedBy = "scenario", cascade = CascadeType.MERGE)     
@LazyCollection(LazyCollectionOption.TRUE)
@JsonManagedReference
private Set<Action> actions = new HashSet<Action>();
}

这样，您可以将Action个实例添加到预定义的Set，并使用Scenario

保存它们

Scenario scenario = new Scenario():
scenario.getActions.add(new Action);
scenarioRepository.save(scenario);

Spring Data REST - 如何同时保存包含子项的父实体

1 个答案: