Android Double Back按此按钮关闭具有片段的应用程序

时间:2015-11-25 07:08:37

标签: android android-fragments onbackpressed

我关注了this tutorial和某些类似的答案。

我目前的onBackPressed代码如下 -

private static final int TIME_DELAY = 2000;
private static long back_pressed;

@Override
public void onBackPressed() {
    DrawerLayout drawer = (DrawerLayout) findViewById(R.id.drawer_layout);
    if (drawer.isDrawerOpen(GravityCompat.START)) {
        drawer.closeDrawer(GravityCompat.START);
    } else {
        int fragments = getFragmentManager().getBackStackEntryCount();
        if (fragments > 0) {
            super.onBackPressed();
        } else {
            if (back_pressed + TIME_DELAY > System.currentTimeMillis()) {
                super.onBackPressed();
            } else {
                Toast.makeText(getBaseContext(), "Press once again to exit!",
                        Toast.LENGTH_SHORT).show();
            }
            back_pressed = System.currentTimeMillis();
        }
    }
}

我正在向这样的堆栈添加片段(在某些地方我不会添加到后台) -

private void LoadSignDetailsFragment() {
    Bundle args = new Bundle();
    Fragment fragment = new SignDetailsFragment();
    args.putBoolean("hasValues", true);
    args.putBoolean("showBookmarkedSignsOnly", showBookmarkedSignsOnly);
    args.putInt("sign_id", signId);
    if (fragment != null) {
        FragmentManager fragmentManager = getActivity().getSupportFragmentManager();
        fragment.setArguments(args);
        FragmentTransaction fragmentTransaction = fragmentManager.beginTransaction();
        fragmentTransaction.setCustomAnimations(R.anim.enter, R.anim.exit, R.anim.pop_enter, R.anim.pop_exit);
        fragmentTransaction.replace(R.id.container_body, fragment);
        fragmentTransaction.addToBackStack(null);
        fragmentTransaction.commit();
    }
}

我要做的是,如果backstack中有任何片段,则单个onBackPressed会迁移到之前的片段。但是,如果在Backstack中没有Fragment,它应该显示Toast for double back press以关闭应用程序。

我现在的代码,总是显示Toast,并要求Double back press,而不管Backstack中是否存在碎片。我无法弄明白为什么?

5 个答案:

答案 0 :(得分:25)

您可以根据需要参考以下代码。如果您不使用v4支持片段,则必须使用getFragmentManager()而不是getSupportFragmentManager()来获取backstack计数。这里我使用布尔值来检查是否单击了后退,如果在2秒内没有再次单击它,它将再次变为假。

boolean doubleBackToExitPressedOnce = false;
@Override
public void onBackPressed() {
    //Checking for fragment count on backstack
    if (getSupportFragmentManager().getBackStackEntryCount() > 0) {
        getSupportFragmentManager().popBackStack();
    } else if (!doubleBackToExitPressedOnce) {
        this.doubleBackToExitPressedOnce = true;
        Toast.makeText(this,"Please click BACK again to exit.", Toast.LENGTH_SHORT).show();

        new Handler().postDelayed(new Runnable() {

            @Override
            public void run() {
                doubleBackToExitPressedOnce = false;
            }
        }, 2000);
    } else {
        super.onBackPressed();
        return;
    }
}

答案 1 :(得分:1)

private boolean doubleBackToExitPressedOnce = true;
    @Override
    public void onBackPressed() {
        DrawerLayout drawer = (DrawerLayout) findViewById(R.id.drawer_layout);
        if (drawer.isDrawerOpen(GravityCompat.START)) {
            drawer.closeDrawer(GravityCompat.START);
        } else {
            if (doubleBackToExitPressedOnce) {
                this.doubleBackToExitPressedOnce = false;
                Toast.makeText(this,"Please click BACK again to exit.", Toast.LENGTH_SHORT).show();
            } else {
                finish();
            }
        }
    }

答案 2 :(得分:0)

以简单的方式做到这一点 使用下面的代码

Boolean doubleBackToExitPressedOnce = false;

@Override
public void onBackPressed() {
    if (doubleBackToExitPressedOnce) {
        super.onBackPressed();

        System.exit(0);

        return;
    }
    this.doubleBackToExitPressedOnce = true;
    Toast.makeText(this, "Please click BACK again to exit",
            Toast.LENGTH_SHORT).show();

}

答案 3 :(得分:0)

在片段onCreateView

中添加此代码
    view.setOnKeyListener( new OnKeyListener()
{
  private Boolean exit = false;
    @Override
    public boolean onKey( View v, int keyCode, KeyEvent event )
    {
        if( keyCode == KeyEvent.KEYCODE_BACK )
        {
        //logic for identifying double back press, expires after 3 seconds
         if (exit) {
            getActivity().finish(); // finish activity
        } else {
            Toast.makeText(this, "Press Back again to Exit.",
                    Toast.LENGTH_SHORT).show();
            exit = true;
            new Handler().postDelayed(new Runnable() {
                @Override
                public void run() {
                    exit = false;
                }
            }, 3 * 1000);

        }
            return true;
        }
        return false;
    }
} );

或者如果你想在你的活动中添加它,你必须覆盖onBackPressed methhod并添加相同的代码。

例如

private Boolean exit = false;

@Override
public void onBackPressed(){

if (exit) {
            finish(); // finish activity
        } else {
            Toast.makeText(this, "Press Back again to Exit.",
                    Toast.LENGTH_SHORT).show();
            exit = true;
            new Handler().postDelayed(new Runnable() {
                @Override
                public void run() {
                    exit = false;
                }
            }, 3 * 1000);

        }    
}

但建议在片段

以外的活动中进行

答案 4 :(得分:0)

没有处理程序的方式:

@Override
public void onBackPressed() { 
    long currentMillis = System.currentTimeMillis();
    if (currentMillis - this.lastPressed < 2000 && getFragmentManager().getBackStackEntryCount() > 0) {
         getFragmentManager().popBackStack();
    } else {
        // show toast if you need
    }
    this.lastPressed = currentMillis;
}