如何将HttpURL连接请求转换为Volly请求?

时间:2015-11-25 11:34:30

标签: android android-volley httpurlconnection

这是我的HttpURLConnection请求正常工作。 我发送json String请求 现在我必须将此请求转换为齐射

  String jsonStr =    {"email":"test@gmail.com","full_name":"vghjj",
                   "locations":[],"mobile_no":"XXXXXXXXX",
                   "super_sectors":    [],"unique_device_id":"XXXXXXX","utm_params":"No Utm Params"}"


try {
        HttpURLConnection urlConnection = getHttpConnection(jsonStr, url, oauth, REQUEST_TYPE.POST.getType());

        if (urlConnection != null) {
            if (urlConnection.getResponseCode() == HttpURLConnection.HTTP_OK) {
                result = convertInputStreamToString(urlConnection.getInputStream());
            } 
        }
    } catch (Exception e) {
        return null;
    } 

private static HttpURLConnection getHttpConnection(String jsonStr , String strUrl, Oauth oauth, String type) {
    URL url = null;
    HttpURLConnection urlConnection = null;

    try {
        url = new URL(strUrl);
        /* */
        if (GlobalVariables.DEVELOPING)
            Log.v(TAG, url.toString());

        urlConnection = (HttpURLConnection) url.openConnection();
        urlConnection.setRequestMethod(type);
        urlConnection.setConnectTimeout(GlobalVariables.applyInternetConnectionTimeOut);
        urlConnection.setReadTimeout(GlobalVariables.applyInternetSocketTimeOut);
        urlConnection.setRequestProperty("Accept", "application/json");
        urlConnection.setRequestProperty("Content-type", "application/json");
        urlConnection.setRequestProperty("Authorization", oauth.getToken_type() + " " + oauth.getAccess_token());

        OutputStream os = urlConnection.getOutputStream();
        os.write(jsonStr.getBytes());
        os.flush();
        os.close();

        return urlConnection;
    } catch (MalformedURLException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
    return null;
}

我已经针对相同的请求编写了这段代码

    StringRequest= new StringRequest(Request.Method.POST, url,
            new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {

                  // Successfull Stuff
                }
            },
            new Response.ErrorListener() {
                @Override
                public void onErrorResponse(VolleyError error) {

                  Log.d(TAG, "onErrorResponse: " + error.toString());

                }
            }
    ) {

        @Override
        protected Map<String, String> getParams() {
            Map<String, String> params = new HashMap<String, String>();
            params.put("allValue", jsonStr);
            return params;
        }

        @Override
        public Map<String, String> getHeaders() throws AuthFailureError {
            Map<String, String> params = new HashMap<String, String>();
            params.put("Content-Type", "application/json");
            params.put("Accept", "application/json");
            params.put("Authorization", oauth.getToken_type() + " " + oauth.getAccess_token());
            return params;
        }
    };

    /*Generate Queue to line up apply request*/
    RequestQueue requestQueue =  VollySingleton.getsInstance().getmRequestQueue();
    requestQueue.add(stringRequest);

所以我的具体问题是 jsonStr在Volley请求中的位置 使用String请求它给出400错误(错误请求) 使用JSonObject Request它会产生500错误

在Http URL Connection中,每个东西都运行良好,jsonStr正在传递

OutputStream os = urlConnection.getOutputStream();
          os.write(jsonStr.getBytes());
        os.flush();
        os.close();

1 个答案:

答案 0 :(得分:0)

这是我解决问题的方法  在事件HttpClient请求中使用的StringEntity的创建对象

<script>

然后覆盖方法

 StringEntity entity = new StringEntity(JsonStr);

所以完整的答案将是

 @Override
        public String getBodyContentType() {
            return entity.getContentType().getValue();
        }

        @Override
        public byte[] getBody() {
            ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
            try {
                entity.writeTo(outputStream);
            } catch (IOException e) {
                VolleyLog.e("IOException @ " + getClass().getSimpleName());
            }
            return outputStream.toByteArray();
        }
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