Question

我想向WebService发送一个对象数组，但是我有 RuntimeException：无法序列化[myClass] 。我尝试了许多创建请求的变体，但没有一个有效。

我的班级调用WebService：

   SoapObject request = new SoapObject(NAMESPACE, NAME);

    com.gt.android.webservice.model.LocationRecord[] table = convertObjects(locationRecords).toArray(new com.gt.android.webservice.model.LocationRecord[locationRecords.size()]);

    SoapObject root = new SoapObject(NAMESPACE, "locRecord");

    for (com.gt.android.webservice.model.LocationRecord i : table){
        root.addProperty("LocationRecord", i);
    }

    request.addSoapObject(root);

    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);

    envelope.dotNet = true;

    envelope.setOutputSoapObject(request);

    envelope.addMapping(NAMESPACE, "LocationRecord", com.gt.android.webservice.model.LocationRecord.class);

    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

    try {
        androidHttpTransport.debug = true;
        androidHttpTransport.call(SOAP_ACTION + NAME, envelope);
... }

首先：我必须从我的列表从一个类转换为另一个类（只是重写字段（以实现平面结构），稍后我尝试创建我的根，添加每个字段，添加序列化，请求，映射和在至少发送我的请求。这是webService结构：

<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
  <soap:Body>
    <SynchonizeLocations xmlns="http://tempuri.org/">
      <locRecord>
        <LocationRecord>
          <id>int</id>
          <logTime>dateTime</logTime>
          <message>string</message>
          <lt>double</lt>
          <lg>double</lg>
          <timestamp>dateTime</timestamp>
          <sessionBestLocation>boolean</sessionBestLocation>
          <number1>int</number1>
          <number2>int</number2>
        </LocationRecord>
        <LocationRecord>
          <id>int</id>
          <logTime>dateTime</logTime>
          <message>string</message>
          <lt>double</lt>
          <lg>double</lg>
          <timestamp>dateTime</timestamp>
          <sessionBestLocation>boolean</sessionBestLocation>
          <number1>int</number1>
          <number2>int</number2>
        </LocationRecord>
      </locRecord>
    </SynchonizeLocations>
  </soap:Body>
</soap:Envelope>

感谢您的帮助。

Answer 1

您可以使用Gson并将对象转换为字符串。

将包含对象数组的新对象类编写为字段。
创建新对象并将数组加载到其中。
使用Gson将对象转换为String：

Gson gson = new Gson（）;
String json = gson.toJson（yourObject）;

示例：

public class LocationRecordsHolder {

    public LocationRecord[] table;

    public LocationRecordsHolder(LocationRecord[] table) {
        this.table = table;
    }

    // Convert object to String
    public static String converToString(LocationRecordHolder obj) {
        Gson gson = new Gson();
        return gson.toJson(obj);
    }

    // Conver String to object
    public static LocationRecordHolder convertFromString(String json) {
        Gson gson = new Gson();
        return gson.fromJson(br, LocationRecordsHolder.class);
    }
}

将对象数组发送到WebService

1 个答案: