以下是我可以用来从邮件中获取所有附件的递归方法。
public List<InputStream> getAttachments(Message message) throws Exception {
Object content = message.getContent();
if (content instanceof String)
return null;
if (content instanceof Multipart) {
Multipart multipart = (Multipart) content;
List<InputStream> result = new ArrayList<InputStream>();
for (int i = 0; i < multipart.getCount(); i++) {
result.addAll(getAttachments(multipart.getBodyPart(i)));
}
return result;
}
return null;
}
private List<InputStream> getAttachments(BodyPart part) throws Exception {
List<InputStream> result = new ArrayList<InputStream>();
Object content = part.getContent();
if (content instanceof InputStream || content instanceof String) {
if (Part.ATTACHMENT.equalsIgnoreCase(part.getDisposition()) || StringUtils.isNotBlank(part.getFileName())) {
result.add(part.getInputStream());
return result;
} else {
return new ArrayList<InputStream>();
}
}
if (content instanceof Multipart) {
Multipart multipart = (Multipart) content;
for (int i = 0; i < multipart.getCount(); i++) {
BodyPart bodyPart = multipart.getBodyPart(i);
result.addAll(getAttachments(bodyPart));
}
}
return result;
}
这可以通过简单地使用迭代来实现而不会递归,因为递归会占用堆栈中相当大的空间吗?