ANTLR：无效的语法 - 在输入时没有可行的替代方案

Question

我正在尝试构建一个简单的语法，但没有成功。我阅读了ANTLR官方文档，但无法弄清问题是什么。以下代码是语法。

grammar Splitter;

splitter : statements EOF;
statements : statement statement*;
statement: (yieldStatement | variableDeclarationStatement | forStatement) ';';
block : '{' statements? '}';

yieldStatement: 'yield' expression;

variableDeclarationStatement: VariableDeclaratorId '=' expression;
VariableDeclaratorId: Identifier;

forStatement: 'for' VariableDeclaratorId 'in' forIterable block;
forIterable: expression;

methodInvocation: MethodName '(' argumentList? ')';
MethodName: Identifier;
argumentList: argumentName (',' argumentName)*;
argumentName: expression;

expression: objectExpression | numericExpression | textExpression | variableAcessor | methodInvocation;
variableAcessor: VariableDeclaratorId ('[' expression ']')*;

objectExpression: '{' keyValueStatementList? '}';
keyValueStatementList: keyValueStatement (',' keyValueStatement)*;
keyValueStatement: keyStatement ':' valueStatement;
keyStatement: textExpression;
valueStatement: expression;

Identifier: [a-zA-Z_]+;

numericExpression : IntegerLiteral;
IntegerLiteral : [0-9]+;

textExpression : '"' StringCharacters? '"';
StringCharacters: StringCharacter StringCharacter*;
fragment StringCharacter: ~["\\] | EscapeSequence;
fragment EscapeSequence: '\\' [btnfr"'\\];

SPACE: [ \t\r\n]+ -> skip;

我的测试是非常简单的输入，不使用所有语法，例如 yield 1; ， yield“a”; 和 DATA = { “关键”：“Hello world”};产量数据; 。

任何？