Question

我有PHP代码，它使用表单中的数字输入值进行某些计算。这些新计算存储在其他变量中，例如：

$weight1 = $priority1 * $savingsAmount;

我想在提交输入表单时将新计算的变量添加到我的MySQL数据库中（它们是在提交表单的同时计算的）。我尝试创建一个SQL查询来执行此操作，但只将表单输入变量添加到数据库中;不会添加通过计算生成的变量值。

我试图返回/调用两个计算函数，但这使我的网页变为空白。如果有人能告诉我捕获这些变量值（在表单提交后计算）的最佳方法是什么，并将它们与表单输入值一起添加到数据库中，我将不胜感激？

编辑我曾尝试调用这两个函数，但我的网页显示为空白，所以我猜测问题在于我如何调用函数。

function weight(&$weight1, &$weight2, &$weight3, $savingsAmount) {

    $priority1 = .40;
    $priority2 = .30;
    $priority3 = .20;

    $weight1 = $priority1 * $savingsAmount;  
    $weight2 = $priority2 * $savingsAmount;
    $weight3 = $priority3 * $savingsAmount;
}

weight(&$weight1, &$weight2, &$weight3, $savingsAmount);

function totalCostPercent(&$totalCost, &$percentage, &$percentageRounded, $cost1, $cost2, $cost3, $savingsAmount) {

    $totalCost = $cost1 + $cost2 + $cost3;
    $percentage = ($savingsAmount / $totalCost) * 100;
    $percentageRounded = ceil($percentage);
}

totalCostPercent(&$totalCost, &$percentage, &$percentageRounded, $cost1, $cost2, $cost3, $savingsAmount);

这是PHP代码，包括SQL查询：

$savingsAmount = "";

$goal1 = "";
$goal2 = "";
$goal3 = "";

$cost1 = "";
$cost2 = "";
$cost3 = "";

$weight1 = "";
$weight2 = "";
$weight3 = "";

$totalCost = "";
$percentageRounded = "";

$display = "display:none;";

// Calcuations
function weight(&$weight1, &$weight2, &$weight3, $savingsAmount) {

    $priority1 = .40;
    $priority2 = .30;
    $priority3 = .20;

    $weight1 = $priority1 * $savingsAmount;  
    $weight2 = $priority2 * $savingsAmount;
    $weight3 = $priority3 * $savingsAmount;
}

function totalCostPercent(&$totalCost, &$percentage, &$percentageRounded, $cost1, $cost2, $cost3, $savingsAmount) {

    $totalCost = $cost1 + $cost2 + $cost3;
    $percentage = ($savingsAmount / $totalCost) * 100;
    $percentageRounded = ceil($percentage);
}


if(isset($_POST['submit'])) {

    $savingsAmount = $_POST['savings-amount'];

    $goal1 = $_POST['goal-1'];
    $cost1 = $_POST['cost-1'];

    $goal2 = $_POST['goal-2'];
    $cost2 = $_POST['cost-2'];

    $goal3 = $_POST['goal-3'];
    $cost3 = $_POST['cost-3'];
    $display = "display:block;";

    $query2 = "INSERT INTO Numbers(Savings, Goal1, Goal2, Goal3, Cost1, Cost2, Cost3, Weight1, 
                Weight2, Weight3, TotalCost, PercentRound) VALUES ('$savingsAmount', '$goal1',  '$goal2',  
                '$goal3',  '$cost1',  '$cost2',  '$cost3',  '$weight1',  '$weight2',  '$weight3', '$totalCost', 
                '$percentageRounded')";

    $result = mysqli_query($dbc, $query2)
    or die ('Error querying request');
}

这是输入表单，以防它方便：

<form action="form.php" method="post" id="savings-form">
            <table>
                <!-- SAVINGS AMOUNT -->
                <tr>
                    <td>Savings Amount: $ </td>
                    <td> <input type="text" id="savings-amount" name="savings-amount" /></td>
                    <td><div id="savingsError"></div></td>
                </tr>

                <tr>
                    <td></td>
                    <td></td>
                </tr>

                <!-- TABLE HEADER-->
                <tr>
                    <td>Priority </td>
                    <td>Savings Goal/Item </td>
                    <td>Cost ($)</td>
                </tr>

                <!-- ROW 1 INFO -->
                <tr>
                    <td>#1</td>
                    <td><input type="text" id="goal-1" name="goal-1" /></td>
                    <td><input type="text" id="cost-1" name="cost-1" /></td>
                </tr>

                <!-- ROW 2 INFO -->

                <tr>
                    <td>#2</td>
                    <td><input type="text" id="goal-2" name="goal-2" /></td>
                    <td><input type="text" id="cost-2" name="cost-2" /></td>
                </tr>

                <!-- ROW 3 INFO-->

                <tr>
                    <td>#3</td>
                    <td><input type="text" id="goal-3" name="goal-3" /></td>
                    <td><input type="text" id="cost-3" name="cost-3" /></td>
                </tr>
                <tr>
                    <td></td>
                    <td></td>
                    <td><div id="costError"></div></td>
                </tr>

                <!-- SUBMIT -->
                <tr>
                    <td><button type="submit" id="submit" name="submit" onclick="return validateSavings() && validateCost();">Submit</button></td>
                </tr>
            </table>
        </form>

这是MySQL表结构：

CREATE TABLE `Numbers` (

`Number` varchar(11), -- Priamry/Foriegn Key
`Savings` varchar(25),
`Goal1` varchar(25),
`Goal2` varchar(25),
`Goal3` varchar(25),
`Cost1` varchar(25),
`Cost2` varchar(25),
`Cost3` varchar(25),
`Weight1` varchar(25),
`Weight2` varchar(25),
`Weight3` varchar(25),
`TotalCost` varchar(25),
`PercentRound` varchar(25)

) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=1;

Answer 1

这些函数在提交函数之外被调用，因此它们将被设置为空白字符串，因为它们设置在页面顶部。

你想做这样的事情：

if(isset($_POST['submit'])) {

    $savingsAmount = $_POST['savings-amount'];

    $goal1 = $_POST['goal-1'];
    $cost1 = $_POST['cost-1'];

    $goal2 = $_POST['goal-2'];
    $cost2 = $_POST['cost-2'];

    $goal3 = $_POST['goal-3'];
    $cost3 = $_POST['cost-3'];
    $display = "display:block;";

    totalCostPercent(&$totalCost, &$percentage, &$percentageRounded, $cost1, $cost2, $cost3, $savingsAmount);
    weight(&$weight1, &$weight2, &$weight3, $savingsAmount);

    $query2 = "INSERT INTO Numbers(Savings, Goal1, Goal2, Goal3, Cost1, Cost2, Cost3, Weight1, 
                Weight2, Weight3, TotalCost, PercentRound) VALUES ('$savingsAmount', '$goal1',  '$goal2',  
                '$goal3',  '$cost1',  '$cost2',  '$cost3',  '$weight1',  '$weight2',  '$weight3', '$totalCost', 
                '$percentageRounded')";

    $result = mysqli_query($dbc, $query2)
    or die ('Error querying request');
}

将函数计算变量添加到MySQL

1 个答案: