Question

初学者问题。我需要为博客创建管理员登录，但我无法接受凭据。登录名是＆＃34; user＆＃34;密码是＆＃34; pwed＆＃34;仅用于测试目的。当我尝试登录时，即使他们不是，我的凭据也是无效的。如果成功，它只是转到管理页面。这应该是一个非常简单的错误，我正在查看，但我希望也许你们中的一个可以帮助我。

这是登录表单

＆＃13;

<form id="form1" name="form1" method="post" action="">
                <p>
                    <label for="name">Account Name:</label>
                    <input type="text" name="login" id="login" /><br/>
                    <label for="name">Password:</label>
                    <input type="text" name="password" id="name" />
                </p>
                <p>
                    <input type="submit" name="Submit1" value="Next &gt;" />
                </p>
            </form>

＆＃13;

这是PHP

<?php

        /* Check to see if there's a form submission */
        if (array_key_exists('Submit1', $_POST)) { // each page needs a different name for the submit button
            session_start();

            // clear any existing session variables because this is the very first page of the survey
            $_SESSION = array();


            /* set required fields */
            //  must be an array, even if only one item is required
            //  if no fields are required, an empty array is needed. Otherwise, in_array() later in the script will generate an error
            $required = array('name', 'password');



            $_SESSION['missing'] = array();

            // process the $_POST variables and save user input in the $_SESSION array
            foreach ($_POST as $key => $value) {
                // assign to temporary variable and strip whitespace if not an array
                $temp = is_array($value) ? $value : trim($value);
                // if empty and required, add to $_SESSION['missing'] array
                if (empty($temp) && in_array($key, $required)) {
                    array_push($_SESSION['missing'], $key);
                }
                // otherwise, assign to a variable of the same name as $key
                else {
                    $_SESSION[$key] = $temp;
                }
            }
            // if no required fields are missing, redirect to the next page
            if (!$_SESSION['missing']) {

              if  ($_SESSION['name'] == "user" && $_SESSION['password'] == "pwed"){
                  // set a variable to control access to other pages, this variable will be checked on all other survey pages
                  $_SESSION['access'] = true;

                  header('Location: svar02.php');
                  exit;

              }
                else {
                    echo "We're sorry your login details seem to be incorrect";
                }
            }
            else{
                echo "It seems you've left a field blank";
            }
            //}
        }
        ?>

Answer 1

我认为问题出在以下位

$required = array('name', 'password');

这需要一个名为name的字段，但您的表单已login，请尝试：

$required = array('login', 'password');

PHP登录凭据即使它们是正确的也不会被验证

1 个答案: