C ++函数循环和if语句不起作用

时间:2015-12-12 06:57:32

标签: c++

所以我想做一个投注游戏。玩家必须输入0到100之间的数字,并且它不能更高或更低。这就是我到目前为止所做的。

int Player_Money = 100;
int Computer_Money = 100;



int Check(int &b) { //b here would be Player_Money
    int Player_Bet = 0;
    bool Exit_Loop = false;

    cout << "Please Enter A Number Between 0 and " << b;

    while (!Exit_Loop) {
        cin >> Player_Bet;
        if (Player_Bet <= 0) {
            cout << "The Amount That You Have Entered Is To Low.\n";
        }

        else if (Player_Bet > b) {
            cout << "The Amount That You Have Entered Is Too High.\n";
        }

        if (Player_Bet > 0) {
            if (Player_Bet < b) {
                Exit_Loop = true;
                if (Player_Bet = b) {
                    cout << "You Have Gone All In!\n";
                    Exit_Loop = true;
                }
            }

        }
        return Player_Bet;
    }
}

当我尝试做Check(变量);这就是发生的事情。

如果它变低,它会说它为低,并退出循环。 如果它很高,它会说你输入的数字很高。然后退出。 如果它在范围内,它表示你全押,返回100,然后退出。

我想知道的是:

*如何正确地进行循环循环以及如何使函数返回正确的数字。

4 个答案:

答案 0 :(得分:0)

如果它在范围内,它表示你全押,返回100,然后退出

if(Player_Bet = b)改变if(Player_Bet == b)因为=将b设置为Player_Bet而==是比较值。

如果您不希望它在具有范围内值之前退出,请移动返回Player_Bet;在while循环中

答案 1 :(得分:0)

首先检查Player_bet是否高于0且低于b。检查之后是否等于b

int Player_Money = 100;
int Computer_Money = 100;

int Check(int &b) { //b here would be Player_Money
    int Player_Bet = 0;
    bool Exit_Loop = false;

    cout << "Please Enter A Number Between 0 and " << b;

    while (!Exit_Loop) {
        cin >> Player_Bet;
        if (Player_Bet <= 0) {
            cout << "The Amount That You Have Entered Is To Low.\n";
        }
        else if (Player_Bet > b) {
            cout << "The Amount That You Have Entered Is Too High.\n";
        }
        else if (Player_Bet > 0 && Player_Bet < b ) {
            Exit_Loop = true;
        }
        else /* if (Player_Bet == b) */ {
            cout << "You Have Gone All In!\n";
            Exit_Loop = true;
        }       
    }
    return Player_Bet;
}

答案 2 :(得分:0)

我在您发布的代码段中看到的一个主要问题是,您的return内的while loop声明 。所以无论Player_Bet的值是什么,总是会在第一次迭代结束时返回并结束方法....换句话说,如果永远不会实际循环。

答案 3 :(得分:0)

您的代码中存在以下几个问题:

  1. 您正在使用=进行比较,您应该使用==
  2. 你正在进行多余的比较。
  3. 您的退出循环没有任何意义,因为您将永远返回。
  4. 这将更适合你。但请注意,做某事(真实)通常不是一个好主意。

    while (true) {
       cin >> Player_Bet;
       if (Player_Bet <= 0) {
           cout << "The Amount That You Have Entered Is To Low.\n";
       } else if (Player_Bet > b) {
           cout << "The Amount That You Have Entered Is Too High.\n";
       } else {
           if (Player_Bet == b) {
               cout << "You Have Gone All In!\n";
           }
           return Player_Bet;
       }
    }
    
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