Question

使用tcl，我想将变量参数传递给函数。我试过这段代码

proc launch_proc { msg proc_name {params {}} } {
    puts "params launch_proc is $params \n"
}
proc test { param } {       
    puts "param test is $param \n"
    launch_proc "1.5.2  test param" test_standard {{*}$param param1 param2 param3"
    }       
}
test value

- ＆GT; params launch_proc是{*} $ param param1 param2 param3＆＃34; $ param未被评估（我使用tcl 8.5）

Answer 1

Tcl支持使用关键字args作为参数列表中的最后一个参数。

以下是directly from the wiki示例：

proc demo {first {second "none"} args} {
    puts "first = $first"
    puts "second = $second"
    puts "args = $args"
}

demo one
demo one two
demo one two three four five

结果

first = one
second = none
args = 
first = one
second = two
args = 
first = one
second = two
args = three four five

您也可以使用扩展语法，这使得以下两次调用等效于demo。

demo one two three four five
set params {three four five}
demo one two {*}$params

Answer 2

您正在传递一个列表，需要将每个项目作为参数发送到proc。

proc test {p1 p2 p3} {
        puts "$p1 - $p2 - $p3"
}

set value {one two three}

# This should work in tcl 8.5+
test {*}$value

set value {four five six}

# For tcl < 8.5
foreach {p1 p2 p3} $value {
        test $p1 $p2 $p3
        break
}

# or

set value {seven eight nine}

test [lindex $value 0] [lindex $value 1] [lindex $value 2]

输出：

$ tclsh test.tcl
one - two - three
four - five - six
seven - eight - nine

Answer 3

您需要upvar，并在构建launch_proc的参数列表时使用list

proc test {varname} {
    upvar 1 $varname value
    puts "param test is $varname => $value"
    launch_proc "1.5.2 test param" test_standard [list {*}$value par1 par2 par3]
}

proc launch_proc {msg proc_name {params {}}} {
    puts "params launch_proc: [join $params ,]"
}

set value {"a b c" "d e f" "g h i"}
test value

param test is value => "a b c" "d e f" "g h i"
params launch_proc: a b c,d e f,g h i,par1,par2,par3

Tcl将变量作为参数传递给函数

3 个答案: