Question

我有一份申请表。这是以前工作但今天它停止正常工作。我提交表单时发生了什么，如果表单有任何错误，它会出现在屏幕上以及网络上。但是当表单提交没有任何错误时，屏幕或网络上不会显示成功消息。也在console.log中尝试过，结果为null。

$bussines_name=$_POST['bussiness_name'];
$email= trim(sanitize_text_field($_POST['emailaddress']));
$url=trim(sanitize_text_field($_POST['websiteaddress']));
$address=trim(sanitize_text_field($_POST['address']));

if(empty($bussines_name) )
    {
        echo json_encode(array(
            'error' => true,
            'msg'   => 'Please enter your Business Name'
        ));
        exit;
    }elseif(empty ($url)){
        echo json_encode(array(
            'error' => true,
            'msg'   => 'Please enter your Unique Booking Code'
        ));
        exit;
    }elseif (empty ($email)) {
        echo json_encode(array(
            'error' => true,
            'msg'   => 'Please enter your email address'
        ));
        exit;
    }elseif(empty($address)){
        echo json_encode(array(
            'error' => true,
            'msg'   => 'Please enter your address'
        ));
        exit;
    } else { echo json_encode(array(
                    'error' => false,
                    'msg'   => 'Form submit successfully.' // **this msg is showing before but not now.**
                     ));

}

ajax请求网址上的代码

swig

任何帮助都会得到赞赏。

Answer 1

＆＃13;

//you have syntax error which i found I have corrected your code. The error was in line no 4 beform function you was using "(" and at last "}" was missing.

$(document).ready(function (e) {
$("#contactForm1").on('submit',function(e) {
    e.preventDefault();
    $('p.error').empty(); 
    $('#loader').show();
	var siteurl = $(this).attr('action');
		$.ajax({
			url: siteurl,
			type: "POST",
			data:  new FormData(this),
			contentType: false,       
			cache: false,
			processData:false,  
			dataType:"json",
			success: function(data){
				if(data.error){
                     $('#loader').hide();
                     $( "p.error" ).empty();
                     $('p.error').css('display','block');
                     $("p.error").append(data.msg);
				}else {
					$('#loader').hide();
					$( "p.error" ).empty();
					$('p.error').css('display','block');
					$("p.error").append(data.msg);
					window.setTimeout(function(){location.reload()},3000)
				}
			}
	   });
	});
});

＆＃13;

ajax错误在失败时出现，但在成功时出现

1 个答案: