Question

我从webservice

跟踪json

"alert": { 
    "long_msg": "Thank you for downloading PHARMAPLUS APP, if you found our APP helpful please rate us five star on play store", 
    "short_msg": "Welcome to PHARMAPLUS", 
    "title": "Thank you" 
 }

我的代码是

 if (json.has("alert")) {
     String alert = json.getString("alert");
     String _title = json.getString(Constansts.PARSE.NOTIFICATION.TITLE);
     String _shortMsg = json.getString(Constansts.PARSE.NOTIFICATION.SHORT_MSG);
     String _longMsg = json.getString(Constansts.PARSE.NOTIFICATION.LONG_MSG);

常量定义如下

 public static final String TITLE = "title";
 public static final String SHORT_MSG = "short_msg";
 public static final String LONG_MSG = "long_msg";

得到如下错误

org.json.JSONException: No value for title

Answer 1

根据JSON

"alert": { 
   "long_msg": "Thank you for downloading PHARMAPLUS APP, if you found our APP helpful please rate us five star on play store", 
   "short_msg": "Welcome to PHARMAPLUS", 
   "title": "Thank you" 
 }

此处提醒是JSONObject。值title，long_msg，short_msg位于alert

内

因此，您需要修改此部分代码

if (json.has("alert")) {
     String alert = json.getString("alert");
     String _title = json.getString(Constansts.PARSE.NOTIFICATION.TITLE);
     String _shortMsg = json.getString(Constansts.PARSE.NOTIFICATION.SHORT_MSG);
     String _longMsg = json.getString(Constansts.PARSE.NOTIFICATION.LONG_MSG);

到

if (json.has("alert")) {
     JSONObject alert = json.getJSONObject("alert");
     String _title = alert.getString(Constansts.PARSE.NOTIFICATION.TITLE);
     String _shortMsg = alert.getString(Constansts.PARSE.NOTIFICATION.SHORT_MSG);
     String _longMsg = alert.getString(Constansts.PARSE.NOTIFICATION.LONG_MSG);

Answer 2

首先在警报下打开JSON，然后在该引用下打包其他字符串值

JSONObject alert=json.getJSONObject("alert");;
String _title = alert.getString(Constansts.PARSE.NOTIFICATION.TITLE);

Answer 3

如果你想要解决这些问题，那么你必须检查响应中的json或字符串是否退出，或者像

一样

JSONObject jsonObject = new JSONObject(respons);///Here response is your response

if(jsonObject.has("alert"))
{
 JSONObject alert = json.getJSONObject("alert");

 if(alert.has("long_msg"))
 {
  String _longMsg = alert.getString(Constansts.PARSE.NOTIFICATION.LONG_MSG);
 }

if(alert.has("short_msg"))
 {
  String _shortMsg = alert.getString(Constansts.PARSE.NOTIFICATION.SHORT_MSG);
 }

if(alert.has("title"))
 {
  String _title = alert.getString(Constansts.PARSE.NOTIFICATION.TITLE);
 }
}

它永远不会抛出异常....你现在得到了什么

Android，org.json.JSONException：没有值

3 个答案: