Question

任何人都可以帮助我，我试图将通过ajax发送的复杂json对象转换为对象。这样我就可以使用这个对象进入我的模型。

JSP代码是：

function callRemovefilter()
{
    var jsonObjects = {
        address1: "Address_1",
        city: "City",
        pin: "PIN"
        };
    var jsonObjects2 = {
        locality:"Loc1",
        shippingType:"Regular",
        shippingCost:20
    };

    var cust= JSON.stringify(jsonObjects);
    var sales=JSON.stringify(jsonObjects2);
    jQuery.ajax({
              url: "http://localhost:8080/OnlineStore/kmsg/grocery/SaveSalesOrder",
              type: "GET",
              data: {CustomerInfo:cust,SalesModel:sales},
              dataType: "json",
              beforeSend: function(x) {
                if (x && x.overrideMimeType) {
                  x.overrideMimeType("application/j-son;charset=UTF-8");
                }
              },
              success: function(result) {
             //Write your code here
              }
    });
}

//控制器代码是

  @RequestMapping(value = "/SaveSalesOrder", method = RequestMethod.GET)
            @ResponseStatus(value=HttpStatus.OK)
            public @ResponseBody String SaveCustomerOrder(@RequestParam Map<String,String> requestParams) throws Exception 
            {       
                ObjectMapper objectMapper = new ObjectMapper();
                SalesCommandObject salesCommandObject= new SalesCommandObject();
                salesCommandObject = objectMapper.readValue(body, SalesCommandObject .class);


                return "Success";
            }

//将对象发送到控制器的JSP代码

var salesCommandObject = {};                      salesCommandObject.CustomerInfo =
            {
            "address1": "Address_1",
            "city": "City",
            "pin": "PIN"
            };
salesCommandObject.SalesModel = 
            {
            "locality":'Loc1',
            "shippingType":'Regular',
            "shippingCost":20
            };

           $.ajax
           ({
              type: "POST",
              dataType : 'json',
              async : true,     
              url: "http://localhost:8080/OnlineStore/kmsg/grocery/SaveSalesOrder",
              data : JSON.stringify(salesCommandObject),
              }).done(function(data,type,xml)
                        {
                                                  console.log(data);
                        }).fail(function()
                                  {
                            alert("Something Bad Happened, Service failed");
                      })

Answer 1

发送对象，而不是jsonstrigs。在你的方法控制器中，SaveCustomerOrder得到一个对象，而不是Map，如：

@RequestMapping(value = "/SaveSalesOrder", method = RequestMethod.GET) @ResponseStatus(value=HttpStatus.OK) public @ResponseBody String SaveCustomerOrder(@RequestParam CustomerInfo ci, @RequestParam SalesModel sm) throws Exception { //your logic here return "Success"; } 并将getter和setter添加到适当的类（即CustomerInfo，SalesModel），如：

`public class SalesModel{
    private String sale_id;//or whatever field or property you need
    public String getSale_Id() {
        return sale_id;
    }
    public void setSale_Id(String si) {
        this.sale_id = si;
    }

}`

如何将JSon对象转换为Java对象？

1 个答案: