如何在python中使用ecdsa签名和验证签名

时间:2015-12-24 10:20:58

标签: python ecdsa

我需要使用256位的私钥来使用ECDSA签署256位的哈希值,就像比特币一样,并且由于缺少python中的ecdsa文档而无法实现绝望。

我在互联网上发现了很多代码,但没有什么比ecdsa.sign(msg, privkey)或类似代码更容易了,我找到的所有内容都是很多我不理解的数学代码,但是他们使用ecdsa库(我不知道为什么他们不会在用于签名的库中添加签名函数,而是在使用库时需要一页代码?)

这是我到目前为止找到的最佳代码:

def ecdsa_sign(val, secret_exponent):
    """Return a signature for the provided hash, using the provided
    random nonce. It is absolutely vital that random_k be an unpredictable
    number in the range [1, self.public_key.point.order()-1].  If
    an attacker can guess random_k, he can compute our private key from a
    single signature. Also, if an attacker knows a few high-order
    bits (or a few low-order bits) of random_k, he can compute our private
    key from many signatures. The generation of nonces with adequate
    cryptographic strength is very difficult and far beyond the scope
    of this comment.

    May raise RuntimeError, in which case retrying with a new
    random value k is in order.
    """
    G = ecdsa.SECP256k1
    n = G.order()
    k = deterministic_generate_k(n, secret_exponent, val)
    p1 = k * G
    r = p1.x()
    if r == 0: raise RuntimeError("amazingly unlucky random number r")
    s = ( ecdsa.numbertheory.inverse_mod( k, n ) * ( val + ( secret_exponent * r ) % n ) ) % n
    if s == 0: raise RuntimeError("amazingly unlucky random number s")

    return signature_to_der(r, s)

def deterministic_generate_k(generator_order, secret_exponent, val, hash_f=hashlib.sha256):
    """
    Generate K value according to https://tools.ietf.org/html/rfc6979
    """
    n = generator_order
    order_size = (bit_length(n) + 7) // 8
    hash_size = hash_f().digest_size
    v = b'\x01' * hash_size
    k = b'\x00' * hash_size
    priv = intbytes.to_bytes(secret_exponent, length=order_size)
    shift = 8 * hash_size - bit_length(n)
    if shift > 0:
        val >>= shift
    if val > n:
        val -= n
    h1 = intbytes.to_bytes(val, length=order_size)
    k = hmac.new(k, v + b'\x00' + priv + h1, hash_f).digest()
    v = hmac.new(k, v, hash_f).digest()
    k = hmac.new(k, v + b'\x01' + priv + h1, hash_f).digest()
    v = hmac.new(k, v, hash_f).digest()

    while 1:
        t = bytearray()

        while len(t) < order_size:
            v = hmac.new(k, v, hash_f).digest()
            t.extend(v)

        k1 = intbytes.from_bytes(bytes(t))

        k1 >>= (len(t)*8 - bit_length(n))
        if k1 >= 1 and k1 < n:
            return k1

        k = hmac.new(k, v + b'\x00', hash_f).digest()
        v = hmac.new(k, v, hash_f).digest()

但我不能相信这样的代码,因为我不知道它的作用。此外,ecdsa_sign中的注释表示返回给定值,秘密指数,和随机数的签名。它说有一个nonce是非常重要的,但我无法弄清楚那个nonce在哪里。

在Windows上使用python中的任何可信库,是否有任何简单的单行方式来签署和验证ECDSA签名?

3 个答案:

答案 0 :(得分:21)

您可以尝试使用python ecdsa包,使用Python3:

pip3 install ecdsa

用法:

import ecdsa

# SECP256k1 is the Bitcoin elliptic curve
sk = ecdsa.SigningKey.generate(curve=ecdsa.SECP256k1) 
vk = sk.get_verifying_key()
sig = sk.sign(b"message")
vk.verify(sig, b"message") # True

使用公钥验证现有签名:

import ecdsa

message = b"message"
public_key = '98cedbb266d9fc38e41a169362708e0509e06b3040a5dfff6e08196f8d9e49cebfb4f4cb12aa7ac34b19f3b29a17f4e5464873f151fd699c2524e0b7843eb383'
sig = '740894121e1c7f33b174153a7349f6899d0a1d2730e9cc59f674921d8aef73532f63edb9c5dba4877074a937448a37c5c485e0d53419297967e95e9b1bef630d'

vk = ecdsa.VerifyingKey.from_string(bytes.fromhex(public_key), curve=ecdsa.SECP256k1)
vk.verify(bytes.fromhex(sig), message) # True

该软件包也与Python 2兼容

答案 1 :(得分:1)

如何安装:

pip install starkbank-ecdsa

如何使用它:

# Generate Keys
privateKey = PrivateKey()
publicKey = privateKey.publicKey()

message = "My test message"

# Generate Signature
signature = Ecdsa.sign(message, privateKey)

# Verify if signature is valid
print Ecdsa.verify(message, signature, publicKey)

完整参考:https://github.com/starkbank/ecdsa-python

答案 2 :(得分:0)

您还可以在Python中使用sep256k1库对ecdsa进行签名和验证。公钥和私钥是从Bip32规范生成的密钥,是从Bip39规范生成的种子。

 Private key  is  1149ab92fbc40993f21336206ca184a9dc2d5231eb575d2a0a6d56773bf0f356
 Public key  is  03c7ac999403591bceacca3d37598886f7c41943c8045c7e1cb5a9295d0003cc5b


from sawtooth_signing.secp256k1 import Secp256k1PrivateKey
from sawtooth_signing.secp256k1 import Secp256k1PublicKey

def sign_nonce(hex_private_key):
   nonce = random.randint(2**10, 2**32)
   checksum = hashlib.sha3_512(str(nonce).encode()).hexdigest()

   private_key = Secp256k1PrivateKey.from_hex(hex_private_key)
   message = private_key.secp256k1_private_key.ecdsa_sign(str(nonce).encode())
   serialized_message = private_key.secp256k1_private_key.ecdsa_serialize(message)
   hex_message = binascii.hexlify(serialized_message)
   return nonce, checksum, hex_message


def verify_nonce(nonce, checksum, message, hex_public_key):
   ##message is hex encoded
   message = binascii.unhexlify(message)
   public_key = Secp256k1PublicKey.from_hex(hex_public_key)
   unserialized = public_key.secp256k1_public_key.ecdsa_deserialize(message)
   result = public_key.secp256k1_public_key.ecdsa_verify(str(nonce).encode(),    unserialized)
  return result

根据验证结果,结果将为True或False。 我已经使用uint32(typings)或int作为随机数,但是可以使用任何字节数组或字符串。字符串需要转换为字节。

相关问题