Question

我使用以下代码序列化从外部服务获取的响应，并返回作为我服务的一部分的json响应。但是，当外部服务返回时间值和时区（10：30：00.000-05.00）时，杰克逊将其转换为15:30:00。如何忽略时区值？

public interface DateFormatMixin {

    @JsonFormat(shape=JsonFormat.Shape.STRING, pattern="HH:mm:ss")
    public XMLGregorianCalendar getStartTime();
    @JsonFormat(shape=JsonFormat.Shape.STRING, pattern="HH:mm:ss")
    public XMLGregorianCalendar getEndTime();
}


public ObjectMapper objectMapper() {
    com.fasterxml.jackson.databind.ObjectMapper responseMapper = new com.fasterxml.jackson.databind.ObjectMapper();
    responseMapper.addMixIn(Time.class, DateFormatMixin.class);
    return responseMapper;
}

Answer 1

您可以创建自定义反序列化器

public class CustomJsonTimeDeserializerWithoutTimeZone extends JsonDeserializer<Time>{

    @Override
    public Time deserialize(JsonParser jp, DeserializationContext ctxt)
            throws IOException, JsonProcessingException {
        DateFormat format = new SimpleDateFormat("hh:mm:ss.SSS");
        Time time = null;
        try{
            Date dt = format.parse("10:30:00.000-05.00".substring(0,12)); // remove incorrect timezone format
            return new Time(dt.getTime());
        }catch (ParseException e){
            e.printStackTrace();
        }
    }

}

告诉杰克逊使用您的自定义反序列化器

public class Model{
    @JsonDeserialize(using = CustomJsonTimeDeserializerWithoutTimeZone.class)
    private Time time;
}

并像这样使用它：

ObjectMapper mapper = new ObjectMapper();

String jsonString = ...// jsonString retrieve from external service
Model model = mapper.readValue(jsonString, Model.class);

您可以使用Jackson Custom Serialization为服务响应添加时区信息

Answer 2

您可以如下创建反序列化器：

public Calendar deserialize(JsonParser jsonParser, DeserializationContext context)
        throws IOException, JsonProcessingException {
    DateFormat formatter = new SimpleDateFormat(("yyyy-MM-dd'T'HH:mm:ss.SSS"));
    String date = jsonParser.getText();
    try {
        Calendar cal = Calendar.getInstance();
        cal.setTime(formatter.parse(date));
        return cal;
    } catch (ParseException e) {
        throw new RuntimeException(e);
    }
}

杰克逊序列化忽略时区

2 个答案: