如何捕获tcp请求包?

时间:2016-01-01 00:58:40

标签: python sockets packet-sniffers sniffing sniffer

我正在尝试ti捕获tcp请求(入站)数据包。正如它在黑帽蟒蛇书中描述的那样,这是嗅探器代码。但是这个嗅探器不捕获tcp请求数据包。我需要从Windows运行环境中捕获。

class IP(Structure):
    _fields_ = [
        ("version", c_ubyte, 4),
        ("ihl", c_ubyte, 4),
        ("tos", c_ubyte),
        ("len", c_ushort),
        ("id", c_ushort),
        ("offset", c_ushort),
        ("ttl", c_ubyte),
        ("protocol_num", c_ubyte),
        ("sum", c_ushort),
        ("src", c_uint32),
        ("dst", c_uint32)
    ]

    def __new__(self, socket_buffer=None):
        return self.from_buffer_copy(socket_buffer)

    def __init__(self, socket_buffer=None):

        # map protocol constants to their names
        self.protocol_map = {1:"ICMP", 6:"TCP", 17:"UDP"}

        self.src_address = socket.inet_ntoa(struct.pack("@I",self.src))
        self.dst_address = socket.inet_ntoa(struct.pack("@I",self.dst))

        # human readable protocol
        try:
            self.protocol = self.protocol_map[self.protocol_num]
        except:
            self.protocol = str(self.protocol_num)

if os.name == "nt":
    socket_protocol = socket.IPPROTO_IP
else:
    socket_protocol = socket.IPPROTO_ICMP

sniffer = socket.socket(socket.AF_INET, socket.SOCK_RAW, socket_protocol)

sniffer.bind((host, 0))
sniffer.setsockopt(socket.IPPROTO_IP, socket.IP_HDRINCL, 1)

# to set up promiscuous mode
if os.name == "nt":
    sniffer.ioctl(socket.SIO_RCVALL, socket.RCVALL_ON)

try:
    while True:
        # read in a packet
        raw_buffer = sniffer.recvfrom(65565)[0]

        # create an IP header from the first 20 bytes of the buffer
        ip_header = IP(raw_buffer[0:])

        # print out the protocol that was detected and the hosts
        print "Protocol: %s %s -> %s " % (ip_header.protocol, ip_header.src_address, ip_header.dst_address)

1 个答案:

答案 0 :(得分:2)

  

我使用过wireshark。它捕获所有传入和传出的数据包。但是python脚本只捕获传出的数据包。

Wireshark使用libpcap / WinPcap,它使用操作系统的数据包捕获机制(libpcap)或由WinPcap(WinPcap)的一部分驱动程序提供的机制来捕获数据包。

您正在使用的机制。鉴于您的代码是Python,您可能希望使用Scapy

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