Question

我正在尝试通过php执行此curl命令，但我无法使用GET请求发送urlencode数据

这是我的卷曲命令

curl -X GET \
-H "X-Parse-Application-Id: ..." \
-H "X-Parse-REST-API-Key: ..." \
-G \
--data-urlencode "where={\"createdAt\": \"2016-01-07T20:38:02.428Z\"}" \
https://api.parse.com/1/classes/Books';

这是我的PHP代码，直到

<?php

header('Content-Type: application/json');

$ParseAppID = "X-Parse-Application-Id: ... " ;
$ParseRestKey = "X-Parse-REST-API-Key: ... " ;
//$ParseMasterKey = ;
$GET ="GET";

$data = array("createdAt"=>"2016-01-09T08:42:36.675Z");
$data_string = json_encode($data);
$curl = curl_init();

curl_setopt($curl, CURLOPT_CUSTOMREQUEST, $GET);
curl_setopt( $curl, CURLOPT_RETURNTRANSFER, 1 );
curl_setopt($curl, CURLOPT_HEADER, FALSE);
curl_setopt($curl, CURLOPT_HTTPHEADER, array($ParseAppID, $ParseRestKey));
curl_setopt($ch, CURLOPT_POSTFIELDS, urlencode('where='.$data_string));
curl_setopt($curl, CURLOPT_URL, "https://api.parse.com/1/classes/Text");

$result = curl_exec( $curl );

curl_close( $curl );
echo $result;
?>

Answer 1

据我所知，对于获取请求，没有POSTFIELDS的等效项，因此您必须将其作为参数添加到网址上。

$("button").click(function() {
   var giftDataArr = [];
   $('tr').each(function() {
     giftDataArr.push({
       pointFrom: $(this).find('.st-points').val(),
       pointTo: $(this).find('.ed-points').val(),
       gift: $(this).find('.gift').val(),
       type: $(this).find('input:radio:checked').val(),
       comment: $(this).find('.comment').val()
     });
   })
   console.log(giftDataArr);
 });

如何将此cURL命令转换为PHP代码

1 个答案: