嵌套联合选择语句

时间:2016-01-12 19:41:35

标签: mysql sql derby javadb

是否可以将我的sql SELECT语句的结果分组,而无需在一个语句中创建临时表并对其进行分组?我有一张表,可以节省信用卡号和借方帐号的借方和贷方金额。 并且为相反的字段放零,我用下面的union select语句做了第一个grouppage我需要根据重复的帐户名称求和 我可以很容易地得到这个或者必须加载临时表吗?我的选择陈述如下

select  journal_drname  AS ACCNAME, sum(amount) AS DEBT,0 as CREDIT
FROM JOURNAL GROUP BY journal_drname 
 UNION select  journal_crname  AS ACCNAME, 0 as DEBT,sum(amount) AS   
 CREDIT,
 FROM JOURNAL GROUP BY journal_crname

返回如下数据:

ACCNAME      DEBIT     CREDIT
--------   -------     ------
CASH        0           1,000
CASH        900          0
CASH        300          0
BANK        200          0
BANK        400          0

我可以在上面进行总结,分组如下:

ACCNAME      DEBIT     CREDIT
--------   -------     ------
CASH        200          0
BANK        600          0

我想加入上述结果。

我试图避免使用临时表,但如果这是实现此目的的唯一实用方法,我想了解更多关于以这种方式使用临时表的信息。

我也试过做某种加入和联合,但不满足条件,我也无法弄清楚如何做到这一点。

3 个答案:

答案 0 :(得分:2)

如果每个子查询只需要一行,则删除group by

select  'CASH' as ACCNAME, sum(amount) AS DEBT, 0 as CREDIT
FROM JOURNAL 
UNION ALL
select  'BANK' as ACCNAME, 0 as DEBT, sum(amount) AS  CREDIT
FROM JOURNAL;

(注意:ACCNAME值可能会反转。)

重要提示:您应该使用UNION ALL来进行此类查询,而不是UNION。除非您打算删除重复项,否则没有理由承担删除重复项的开销。

此外,您的原始查询应该有效,除非accname字段中有异常字符。

答案 1 :(得分:2)

正如您所说的查询有效,我们可以将您的联合查询称为表

( ...... ) myTable

然后创建一个子查询以获得最后一步

SELECT ACCNAME,
       CASE WHEN SUM(CREDIT - DEBT) < 0 THEN - SUM(CREDIT - DEBT)
            ELSE 0
       END DEBT,
       CASE WHEN SUM(CREDIT - DEBT) > 0 THEN   SUM(CREDIT - DEBT)
            ELSE 0
       END CREDIT
FROM ( ...... ) myTable
GROUP BY ACCNAME

答案 2 :(得分:1)

怎么样:

select ACCNAME, 
    CASE WHEN sum(DEBT)>sum(CREDIT) THEN sum(DEBT)-sum(CREDIT) ELSE 0 AS DEBT, 
    CASE WHEN sum(DEBT)<sum(CREDIT) THEN sum(CREDIT)-sum(DEBT) ELSE 0 AS CREDIT 
FROM (
    select  journal_drname  AS ACCNAME, 
        sum(amount) AS DEBT,
        0 as CREDIT
    FROM JOURNAL GROUP BY journal_drname 
UNION 
    select journal_crname  AS ACCNAME, 
        0 as DEBT,
        sum(amount) AS CREDIT,
 FROM JOURNAL GROUP BY journal_crname
) group by ACCNAME
相关问题