Question

我想打开同一个应用程序的新实例，就像打开新标签页时(See this)

默认使用的Chrome一样

这是我到目前为止所尝试的内容：

PackageManager pm = getContext().getPackageManager();
Intent launcher = pm.getLaunchIntentForPackage("my.package.name");
launcher.setAction(Intent.ACTION_VIEW);
launcher.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
launcher.setData(Uri.parse(result.getExtra()));
getContext().startActivity(launcher);

它确实启动了一项新活动，并且还加载了正确的数据，但它没有打开新的屏幕。

我将如何实现这一目标？

这是我的最终文件

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
    package="eu.depa.browsing.stack">

    <uses-permission android:name="android.permission.INTERNET"/>
    <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE"/>
    <uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE"/>
    <uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE"/>
    <uses-permission android:name="com.android.launcher.permission.INSTALL_SHORTCUT" />
    <uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />

    <application
        android:fullBackupContent="true"
        android:allowBackup="true"
        android:icon="@mipmap/ic_launcher"
        android:label="@string/app_name"
        android:supportsRtl="true"
        android:theme="@style/AppTheme"
        android:hardwareAccelerated="true">

        <activity android:name=".MainActivity"
            android:configChanges="orientation|keyboardHidden|screenSize"
            android:windowSoftInputMode="stateAlwaysHidden"
            android:targetActivity=".MainActivity"
            android:icon="@mipmap/ic_launcher">
            <intent-filter>
                <action android:name="android.intent.action.VIEW" />
                <category android:name="android.intent.category.DEFAULT" />
                <category android:name="android.intent.category.BROWSABLE" />
                <data android:scheme="http"  />
                <data android:scheme="https" />
            </intent-filter>
            <intent-filter>
                <action android:name="android.intent.action.MAIN" />
                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
        </activity>

        <activity android:name=".About"/>
        <activity android:name=".Donate"/>
        <activity android:name=".Settings"/>
        <activity android:name=".GPL"/>
        <activity android:name=".History"/>

        <!-- ATTENTION: This was auto-generated to add Google Play services to your project for
             App Indexing.  See https://g.co/AppIndexing/AndroidStudio for more information. -->
        <meta-data
            android:name="com.google.android.gms.version"
            android:value="@integer/google_play_services_version" />
    </application>

</manifest>

如何打开同一个应用程序的新实例？

0 个答案: