Question

我是一个前端开发人员，玩后端所以请耐心等待。我只是创建一个简单的应用程序，显示足球比赛的团队阵容。我已经在数据库中创建了表格，并且可以遍历所有22个玩家进行比赛。但是，我只想在一个div中显示前11个而在另一个div中显示第二个11。

到目前为止，这是我的代码：

    <?php

try {

    $handler = new PDO('mysql:host=localhost;dbname=euro_missing_men','root','');
    $handler->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

} catch(PDOException $e) {
    echo $e->getMessage();
    die('Sorry, database issue');
}




$query = $handler->query('SELECT * FROM `game` g 
    JOIN team t on (g.id = t.game_id) 
    JOIN team_name tn on (t.team_id = tn.id)
    JOIN position p on (t.position_id = p.id)
');

$results = $query->fetch(PDO::FETCH_OBJ);

while($row = $query->fetch(PDO::FETCH_OBJ)) {
    echo $row->player, "<br/>";
}


?>

这会产生以下结果：

McKimmie
Calderwood
Hendry
Boyd
McKinlay
McCall
McAllister
Collins
Spencer
Durie
Seaman
Neville
Adams
Southgate
Pearce
Anderton
Ince
Gascoigne
McManaman
Sheringham
Shearer

但我想将它们分开。我知道可能有更好的方法来做这个，但为了练习的目的，我想在一个div中回应前11个名字，在另一个div中回应第二个11个名字。

感谢。

Answer 1

// create a counter
$i = 0;

// echo the opening div
echo "<div>";
while($row = $query->fetch(PDO::FETCH_OBJ)) {
    echo $row->player, "<br/>";
    if ( $i++ == 11 ) echo "</div><div>"; // increment the counter and at the 11th iteration close the div and start a new one
}
echo "</div>";

Answer 2

这假设你可能有22个以上。如果你只有22个，那么@pamblam有更简单的答案。

如果您想将它们分成11组，您可以使用modulus运算符：

var $count = 1;
while($row = $query->fetch(PDO::FETCH_OBJ)) {
    // After every 11th row, echo a closing div / open a new div
    if ( ! ($count++ % 11) ) {
        echo '</div><div>';
    }

    // Don't use break tags, you can't style them well.
    echo '<p>' . $row->player . "</p>";
}

或者，另一种方法是将结果分成数组：

$results = $query->fetchAll();

$divs = array_chunk($results, 11);

foreach( $divs AS $div ) {
    echo '<div>';
    foreach ( $div AS $row ) {
        echo '<p>' . $row->player . '</p>';
    }
    echo '<div>';
}

Answer 3

简单分割结果？然后循环每一个？

$results = $query->fetchAll();

$team1 = array_slice($results, 0, 11);

$team2 = array_slice($results, 11);

如建议的array_chunck

$results = $query->fetchAll();

$teams = array_chunk($results, 11);

并输出此

$results = $query->fetchAll(PDO::FETCH_OBJ);

$teams = array_chunk($results, 11);

foreach($teams as $team) {
    echo '<div>';
    foreach($team as $player) {
        echo $player->name . '<br />';
    }
    echo '</div>';
}

Answer 4

你总是可以做一些基本的事情：

   <?php

try {

    $handler = new PDO('mysql:host=localhost;dbname=euro_missing_men','root','');
    $handler->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

} catch(PDOException $e) {
    echo $e->getMessage();
    die('Sorry, database issue');
}




$query = $handler->query('SELECT * FROM `game` g 
    JOIN team t on (g.id = t.game_id) 
    JOIN team_name tn on (t.team_id = tn.id)
    JOIN position p on (t.position_id = p.id)
');

$results = $query->fetch(PDO::FETCH_OBJ);
$upto = 0;
echo "<div>"; //Start the divs
while($row = $query->fetch(PDO::FETCH_OBJ)) {
    $upto ++; //add 1 to upto
    if($upto % 11 == 0) //if 11 results
        echo "</div><div>"; //create new div
    echo $row->player, "<br/>";

}
echo "</div>"; //close div


?>

Answer 5

您可以添加增量。如果$ i＆lt; = 11将玩家放入第一个div。换句话说，把它们放到第二个div。

    $results = $query->fetch(PDO::FETCH_OBJ);
    $i = 0;

    while($row = $query->fetch(PDO::FETCH_OBJ)) {
     $i++;
     if($i <= 11){
        echo "{$i} of 22".$row->player."<br/>";
     }
     else{
        echo "{$i} of 22".$row->player."<br/>";
     }
    }

从数据库中回显一组特定的行

5 个答案: