Question

我有php脚本，它从sql server运行存储过程，并在数据库中的表中输入数据。当我运行php脚本时，它进入重复日期，即使数据库中存在相同的数据。我需要摆脱这些重复的数据。存储过程给了我正确的输出，但是这个PHP脚本让我很烦恼

     while ($obj = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC  ))
{

     if($obj['Bank_Name']!= $obj['Bank_Name_old'])
            {       
            $obj['company_code']; 
            $obj['Account_Code'];
            $obj['Bank_Name']; 
            $obj['Bank_Name_old'];
            $obj['field_name']='Bank Name';

             if($obj['field_name']='Bank Name')
            {   
                $old=$obj['Bank_Name_old'];     
                $new=$obj['Bank_Name']; 
            }
                    $query="insert into vns_db.dbo.client_details_log (company_code,client_id,field_name,original_value,new_value) values ('".$obj['company_code']."',
                            '".$obj['Account_Code']."','".$obj['field_name']."','$old','$new')";    
                            $res = sqlsrv_query($conn,$query);
                            //$obj['modified_fields']=$obj['field_name'].'|'.addslashes('$old').'|'.addslashes('$new');

                        //  echo $query;
            }   
        if($obj['Bank_AcNo'] != $obj['Bank_AcNo_old'])
            {
                     $obj['company_code']; 
                     $obj['Account_Code'];
                     $obj['Bank_AcNo']; 
                     $obj['Bank_AcNo_old'];
                     $obj['field_name']='Bank account number';

                        if($obj['field_name']='Bank account number')
            {   
                    $old=$obj['Bank_AcNo_old']; 
                    $new=$obj['Bank_AcNo'];         
            }
                     $query="insert into vns_db.dbo.client_details_log (company_code,client_id,field_name,original_value,new_value) values ('".$obj['company_code']."',
                            '".$obj['Account_Code']."','".$obj['field_name']."','$old','$new')"; 
                            $res = sqlsrv_query($conn,$query);
                            //$obj['modified_fields']=$obj['field_name'].'|'.addslashes('$old').'|'.addslashes('$new');
                            //echo $query;

            }

Answer 1

如果循环中的条件有可能同时执行：

if($obj['Bank_Name']!= $obj['Bank_Name_old'])

和

if($obj['Bank_AcNo'] != $obj['Bank_AcNo_old'])

这可能会插入两次试用：）

Answer 2

如果if($obj['Bank_Name']!= $obj['Bank_Name_old'])和if($obj['Bank_AcNo'] != $obj['Bank_AcNo_old'])都是true，则会将两个数据集添加到表client_details_log。

如果if语句if($obj['field_name']='Bank account number')为false，则不会更新变量$old和$new，以便将相同的数据添加到表中两次。

也许你必须在你的if($obj['field_name'] == ...)语句中移动你的SQL查询：

if($obj['field_name'] == 'Bank Name')
{
    $old=$obj['Bank_Name_old'];     
    $new=$obj['Bank_Name']; 

    $query="insert into vns_db.dbo.client_details_log (company_code,client_id,field_name,original_value,new_value) values ('".$obj['company_code']."', '".$obj['Account_Code']."','".$obj['field_name']."','$old','$new')";

    $res = sqlsrv_query($conn,$query);
}

Answer 3

有一两件事可能会对您的代码造成问题。首先，正如Devanshu所说，你可以复制（见下面的推荐）。其次，if语句分配（=）而不是比较（==）。第三，你应该尝试使用函数而不是复制可能使调试变得困难的代码。

尝试这样的事情：

function addData()
{
    $query = "insert into vns_db.dbo.client_details_log (company_code,client_id,field_name,original_value,new_value) values ('".$obj['company_code']."',
            '".$obj['Account_Code']."','".$obj['field_name']."','".$old."','".$new."')";    
    return sqlsrv_query($conn,$query);
}

while ($obj = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC  ))
{

     if ( ($obj['Bank_Name']!= $obj['Bank_Name_old']) || ($obj['Bank_AcNo'] != $obj['Bank_AcNo_old']) )
    {       
        $obj['company_code']; 
        $obj['Account_Code'];
        $obj['Bank_Name']; 
        $obj['Bank_Name_old'];
        $obj['field_name']='Bank Name';

         if ($obj['field_name']=='Bank Name')
        {   
            $old=$obj['Bank_Name_old'];     
            $new=$obj['Bank_Name']; 
        }

        if ($obj['field_name']=='Bank account number')
        {   
            $old=$obj['Bank_AcNo_old']; 
            $new=$obj['Bank_AcNo'];         
        }       

        $res = addData();
    }   

}

php脚本在数据库中输入重复数据

3 个答案: