此原始查询的等效sequelize查询是什么？

Question

SELECT offers.id FROM提供WHERE offers.user_id！=＆＃39; 2＆＃39;和offers.id不在（从notifications_offers.user_id =＆＃39; 2＆＃39;）中选择notifications_offers.offer_id from informed_offers;

Answer 1

如果您已关联Offers和NotifiedOffers模型，并且它不是多对多关联，则可以执行以下操作：

Offers.findAll({
    attributes: ['id'],
    where: {
        user_id: {
            not: 2
        }
    },
    include: {
        model: NotifiedOffers,
        where: {
            user_id: {
                not: 2
            }
        },
        required: true
    }
});