Question

我正在尝试编写一个select语句，为每个名称收集一行。因此预期的产出是：

名称= Al，薪水= 30，奖金= 10

TABLE_1

Name   Salary
Al     10
Al     20

TABLE_2

Name  Bonus
Al    5
Al    5

我该怎么写？我试着：

Select t1.Name, SUM(t1.Salary), SUM(t2.Bonus) FROM table_1 t1
LEFT JOIN table_2 t2 
ON t1.Name=t2.Name
Group By 1

我获得奖金20而不是10奖金。这可能是因为t1中有两行累加奖金。如何修改我的功能以获得正确的奖金？

Answer 1

按员工分别对表进行分组，然后加入它们：

SELECT t1.Name, Salary, Bonus
FROM (
  SELECT Name, SUM(Salary) Salary
  FROM table_1
  GROUP BY Name
) t1
LEFT JOIN (
  SELECT Name, SUM(Bonus) Bonus
  FROM table_2
  GROUP BY Name
) t2 ON t1.Name = t2.Name

Answer 2

您可以使用这样的子查询来执行此操作：

declare @salary table (Name varchar(100), value int)
declare @bonus table (Name varchar(100), value int)

insert into @salary
values ('al', 10)

insert into @salary
values ('al', 20)

insert into @bonus
values ('al', 5)

insert into @bonus
values ('al', 5)


select s.Name, sum(value) as Salary, Bonus
from @salary s JOIN 
(
    select Name, sum(value) as Bonus
    from @bonus 
    group by Name 
) b on b.name = s.Name
group by s.Name, b.Bonus

Answer 3

SELECT 
  coalesce(t1.name,t2.name) name, 
  coalesce(sum(t1.salary),0) salary_total, 
  coalesce(sum(t2.bonus),0) bonus_total
FROM 
  (select name, sum(salary) salary from salary_table group by 1) t1
FULL OUTER JOIN 
  (select name, sum(bonus) bonus from bonus_table group by 1) t2
ON (t1.name=t2.name)
GROUP BY 1
;

加入给出错误的总和

3 个答案: