我需要使用网址在锦标赛中注册:
http://laravel.dev/tournaments/1/register/
此URL位于中间件'auth'中,因此如果用户未登录,则会将其重定向到登录页面。
我需要的是重定向到
http://laravel.dev/tournaments/1/register/
社交登录后(我有2个提供商,fb和google)
在这种情况下,我不希望将用户重定向到.env中定义的重定向网址
这是我使用社交网站登录时使用的功能:
public function execute($request, $listener, $provider) {
if (!$request) {
return $this->getAuthorizationFirst($provider);
}
$user = $this->users->findByUserNameOrCreate($this->getSocialUser($provider), $provider);
if (!is_null($user)){
$this->auth->login($user, true);
}else{
Session::flash('error', Lang::get('auth.account_already_exists'));
return redirect('auth/login');
}
return $listener->userHasLoggedIn($user);
}
如何让系统将我重定向到初始操作,而不是默认的redirect_url参数。
我通过guest()函数正常登录解决了这个问题,但在这种情况下我不知道如何实现它。
问题与此post
非常相似答案 0 :(得分:4)
关键功能是guest()
和intended()
:
guest()
创建对您选择的网址的重定向回复,
理想情况下,您的登录页面,同时将当前网址存储在您的位置
可以将用户重定向到,当后者成功完成时
身份验证过程。
intended()
在用户之后获取预期的重定向网址
完成身份验证。
<强>演示强>
Authenticate
中间件 - 用于验证访问该网址的用户是否已登录。
class Authenticate
{
/**
* Handle an incoming request.
*
* @param \Illuminate\Http\Request $request
* @param \Closure $next
* @return mixed
*/
public function handle($request, Closure $next)
{
//check if user is not logged in.
if (Sentinel::check() === false) {
//If ajax, send back ajax response
if ($request->ajax()) {
return response('Unauthorized.', 401);
} else {
//redirect guest to login page
return redirect()->guest('/login');
}
}
return $next($request);
}
}
RESTful UserController
,我们处理所有登录尝试
/**
* POST: Login
*
* @param Request $request
* @return $this|\Illuminate\Http\RedirectResponse|\Illuminate\Http\Response
*/
public function postLogin(Request $request)
{
//Authenticate User if possible
if ($this->service->user->loginByEmail($request->only(['email','password','remember_me']))) {
//Authentication Successful - Redirect to url that guest was trying to access, else redirect to home page.
return redirect()->intended('/');
} else {
//Authentication error, redirect back to login page with input
return redirect('/login')->withErrors(['password_incorrect' => 'Your password is incorrect. Please try again.'])->withInput();
}
}
已在框架中的函数声明
Illuminate\Routing\Redirector
/**
* Create a new redirect response, while putting the current URL in the session.
*
* @param string $path
* @param int $status
* @param array $headers
* @param bool $secure
* @return \Illuminate\Http\RedirectResponse
*/
public function guest($path, $status = 302, $headers = [], $secure = null)
{
//Store current full URL in session
$this->session->put('url.intended', $this->generator->full());
//Redirect
return $this->to($path, $status, $headers, $secure);
}
/**
* Create a new redirect response to the previously intended location.
*
* @param string $default
* @param int $status
* @param array $headers
* @param bool $secure
* @return \Illuminate\Http\RedirectResponse
*/
public function intended($default = '/', $status = 302, $headers = [], $secure = null)
{
//Get path that guest was trying to access
$path = $this->session->pull('url.intended', $default);
//Redirect
return $this->to($path, $status, $headers, $secure);
}
答案 1 :(得分:1)
像这样使用:return redirect()->guest('auth/login');
。