Question

我正在使用会话进行登录功能。但是，每次我尝试登录时，都会重定向到登录屏幕。下面是代码。有一个函数设置说登录无效，不发送错误所以我不确定它是登录问题。

ATIS控制器

<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');

class Atis extends CI_Controller 
{
        public $status; 
        public $roles;
function __construct()
    {
        parent::__construct();
    $this->load->model('User_model', 'user_model', TRUE);
    $this->status = $this->config->item('status'); 
    $this->roles = $this->config->item('roles');    
    $this->is_logged_in();
    }

function index(){   
    $this->load->view("atis/inc/header");
    $this->load->view("atis/dashboard");
    $this->load->view("atis/inc/footer");
    }
function is_logged_in()
{
    $is_logged_in = $this->session->userdata('is_logged_in');
    if(!isset($is_logged_in) || is_logged_in !==true)
    {
        redirect('main/login');
    }
}

主要控制器

 public function login()
        {
            $this->form_validation->set_rules('email', 'Email', 'required|valid_email');    
            $this->form_validation->set_rules('password', 'Password', 'required'); 

            if($this->form_validation->run() == FALSE) {
                $this->load->view('inc/site_header');
                $this->load->view("site_nav"); 
                $this->load->view('login');
                $this->load->view('inc/site_footer');
            }else{

                $post = $this->input->post();  
                $clean = $this->security->xss_clean($post);

                $userInfo = $this->user_model->checkLogin($clean);

                if(!$userInfo){
                    $this->session->set_flashdata('flash_message', 'The login was unsucessful');
                    redirect(site_url().'main/login');
                }                
                foreach($userInfo as $key=>$val){
                    $this->session->set_userdata($key, $val);
                    $this->session->set_userdata('is_logged_in');
                }
                redirect(site_url().'atis/');
            }

        }

检查登录方式

public function checkLogin($post)
    {
        $this->load->library('password');       
        $this->db->select('*');
        $this->db->where('email', $post['email']);
        $query = $this->db->get('users');
        $userInfo = $query->row();

        if(!$this->password->validate_password($post['password'], $userInfo->password)){
            error_log('Unsuccessful login attempt('.$post['email'].')');
            return false; 
        }

        $this->updateLoginTime($userInfo->id);

        unset($userInfo->password);
        return $userInfo; 
    }

ATIS控制器的场地功能

public function yard()

    {
        $this->load->model('atisyard_model');
        $this->data['yards'] = $this->atisyard_model->getyardname();
        $this->data['trackdatabase'] = $this->atisyard_model->gettrains();
        $this->load->view("atis/inc/header");
        $this->load->view('atis/yard_view', $this->data);
        $this->load->view("atis/inc/footer");
    }

Answer 1

{1}}

中缺少$

或者如果仍然无效，请尝试更改

if(!isset($is_logged_in) || is_logged_in !==true)

到

if(!isset($is_logged_in) || is_logged_in !==true)

Answer 2

$this->session->set_userdata('is_logged_in');

不正确。你应该传递像

这样的东西

$this->session->set_userdata('is_logged_in', TRUE);

或

$this->session->set_userdata($arr);

让它有效。 Docs

编辑：

在控制器中，更改此

if(!$userInfo)
{
    $this->session->set_flashdata('flash_message', 'The login was unsucessful');
    redirect(site_url().'main/login');
}
foreach($userInfo as $key=>$val)
{
    $this->session->set_userdata($key, $val);
    $this->session->set_userdata('is_logged_in');
}
redirect(site_url().'atis/');

到这个

if(!$userInfo)
{
    $this->session->set_flashdata('flash_message', 'The login was unsucessful');
    redirect(site_url().'main/login');
}
else
{
    foreach($userInfo as $key=>$val)
    {
        $this->session->set_userdata($key, $val);
    }
    $this->session->set_userdata('is_logged_in', TRUE);
    redirect(site_url().'atis/');
}

编辑：20160130002859

在is_logged_in()方法中，您正在检查if(!isset($is_logged_in) || $is_logged_in !==true)这是否是悖论。在任何情况下，条件的右侧都是FALSE。这是因为事实$is_logged_in如果没有显式转换，则nevere可以按类型布尔TRUE。这是对象。所以你应该以其他方式检查：

$is_logged_in != TRUE // this way you don't check for type

或

is_object($is_logged_in)

用户登录将重定向回登录代码点火器

2 个答案: