Question

我有两张桌子。下面给出了table1和table2之类的东西：
table1具有ID（主键）和列Aid，Bid和Cid，它们是表2的主键。

table1

ID  Aid Bid Cid
-----------------
1   X   Y   Z
2   X   Z   Z
3   Y   X   X
-----------------

table2

ID  NAME
------------------
X   Abc
Y   Bcd
Z   Cde
------------------

我想要一个查询，以这种方式从table1中获取所有列（在用表2中给出的相应名称替换Aid，Bid和Cid之后）：

    ID   A   B   C
    1   Abc Bcd Cde
    2   Abc Cde Cde
    3   Bcd Abc Abc

你能告诉我mysql查询吗？

非常感谢您的回答。但是当我执行这些查询时，我会开始这样做：

+------+------+------+------+
| ID   | A    | B    | C    |
+------+------+------+------+
|    3 | bcd  | abc  | abc  |
|    1 | abc  | bcd  | cde  |
|    2 | abc  | cde  | cde  |
+------+------+------+------+

此查询：SELECT * FROM table1 JOIN table2 aa ON table1.Aid = aa.ID JOIN table2 bb ON table1.Bid = bb.ID JOIN table2 cc ON table1.Cid = cc.ID;

给出了这个结果：

+------+------+------+------+------+------+------+------+------+------+
| ID   | Aid  | Bid  | Cid  | ID   | NAME | ID   | NAME | ID   | NAME |
+------+------+------+------+------+------+------+------+------+------+
|    3 | Y    | X    | X    | Y    | bcd  | X    | abc  | X    | abc  |
|    1 | X    | Y    | Z    | X    | abc  | Y    | bcd  | Z    | cde  |
|    2 | X    | Z    | Z    | X    | abc  | Z    | cde  | Z    | cde  |
+------+------+------+------+------+------+------+------+------+------+

我认为查询需要稍微修改一下..

Answer 1

这应该有效：

select table1.ID, a.NAME AS A, b.NAME AS B, c.NAME AS C
from table1 
join table2 a on table1.Aid = a.ID 
join table2 b on table1.Bid = b.ID 
join table2 c on table1.Cid = c.ID

否则：

select table1.ID, a.NAME, b.NAME, c.NAME from table1 join (select * from table2) a on table1.Aid = a.ID join (select * from table2) b on table1.Bid = b.ID join (select * from table2) c on table1.Cid = c.ID

Answer 2

你可以试试这个。 INNER JOIN＆amp; ORDER -

SELECT a.ID, b.NAME, c.NAME, d.NAME
FROM table1 a
INNER JOIN table2 b ON b.ID = a.Aid
INNER JOIN table2 c ON c.ID = a.Bid
INNER JOIN table2 d ON d.ID = a.Aid
ORDER BY a.ID

Answer 3

SELECT table1.ID, aa.NAME A, bb.NAME B, cc.NAME C
FROM table1
JOIN table2 aa ON table1.Aid = aa.ID
JOIN table2 bb ON table1.Bid = bb.ID
JOIN table2 cc ON table1.Cid = cc.ID

Answer 4

这应该适合你：

SELECT t1.ID, t2a.NAME as A, t2b.NAME as B, t2c.NAME as C
from table1 t1
INNER JOIN table2 t2a ON t1.Aid = t2a.ID 
INNER JOIN table2 t2b ON t1.Bid = t2b.ID 
INNER JOIN table2 t2c ON t1.Cid = t2c.ID
ORDER BY t1.ID ASC

Answer 5

你可以尝试以下查询，因为我已经用我的mysql手动检查了它：

SELECT ID,(SELECT NAME FROM table2 as t2 WHERE t1.Aid=t2.ID) as A,(SELECT NAME FROM table2 as t2 WHERE t1.Bid=t2.ID) as B,(SELECT NAME FROM table2 as t2 WHERE t1.Cid=t2.ID) as C FROM table1 AS t1

由于

Answer 6

您可以使用以下查询来获得所需的结果：

SELECT t1.ID AS ID, a.NAME AS A, b.NAME AS B, c.NAME AS C FROM (table1 t1, table2 a, table2 b, table2 c) WHERE (t1.Aid = a.ID AND t1.Bid = b.ID AND t1.Cid = c.ID) ORDER BY t1.ID;

带内连接的Mysql查询

6 个答案: