如何按照孩子的子女数量对EF父母进行排序?

时间:2016-02-02 22:06:35

标签: c# sql sql-server entity-framework

任务项目编码器团队

如何使用方法语法和Code First方法(实体框架中的任务的数量有效地对团队进行排序(可能不会加载子项的子集的整个集合内容) ,我只需要排序)?

public class MyAppContext : DbContext
{
    public DbSet<CTeam> Teams { get; set; }
    // ...etc
}

[Table("Team")]
public class CTeam
{

    public int ID { get; set; }

    [MaxLength(128)]
    public string Title { get; set; }

    [Display(Name = "Coders")]
    public virtual ICollection<CCoder> Coders { get; set; }
}



[Table("Coder")]
public class CCoder
{

    public int ID { get; set; }

    [MaxLength(128)]
    public string Name { get; set; }

    public virtual ICollection<CProject> Projects { get; set; }

    public int TeamID { get; set; }
    public virtual CTeam Team { get; set; }
}

//  CProject and CTask similarly

或者,如果你能给出一个提示原始SQL应该是什么样的提示,这也会有所帮助。谢谢!

更新

在关系Builder -> NewBuildingObject -> NewBuildingHouse -> NewBuildingLayout

的项目中

为了观众的方便, Teodor Ivanov 的回答:

context.Teams
.OrderBy(x => x.Coders
   .SelectMany(y => y.Projects)
   .SelectMany(y => y.Tasks)
   .Count());

使EF生成此代码:

SELECT 
    [Project1].[ID] AS [ID], 
    [Project1].[Title] AS [Title]
    FROM ( SELECT 
        [Extent1].[ID] AS [ID], 
        [Extent1].[Title] AS [Title], 
        (SELECT 
            COUNT(1) AS [A1]
            FROM   [dbo].[NewBuildingObject] AS [Extent2]
            INNER JOIN [dbo].[NewBuildingHouse] AS [Extent3] ON [Extent2].[ID] = [Extent3].[ObjectID]
            INNER JOIN [dbo].[NewBuildingLayout] AS [Extent4] ON [Extent3].[ID] = [Extent4].[HouseID]
            WHERE [Extent1].[ID] = [Extent2].[BuilderID]) AS [C1]
        FROM [dbo].[Builder] AS [Extent1]
    )  AS [Project1]
    ORDER BY [Project1].[C1] ASC

Yacoub Massad 的回答:

var teams = context.Teams
    .OrderBy(team =>
        team.Coders.SelectMany(coder =>
            coder.Projects.SelectMany(project => project.Tasks)).Count());

制作了这段代码:

SELECT 
    [Project1].[ID] AS [ID], 
    [Project1].[Title] AS [Title]
    FROM ( SELECT 
        [Extent1].[ID] AS [ID], 
        [Extent1].[Title] AS [Title], 
        (SELECT 
            COUNT(1) AS [A1]
            FROM  [dbo].[NewBuildingObject] AS [Extent2]
            INNER JOIN  (SELECT [Extent3].[ObjectID] AS [ObjectID]
                FROM  [dbo].[NewBuildingHouse] AS [Extent3]
                INNER JOIN [dbo].[NewBuildingLayout] AS [Extent4] ON [Extent3].[ID] = [Extent4].[HouseID] ) AS [Join1] ON [Extent2].[ID] = [Join1].[ObjectID]
            WHERE [Extent1].[ID] = [Extent2].[BuilderID]) AS [C1]
        FROM [dbo].[Builder] AS [Extent1]
    )  AS [Project1]
    ORDER BY [Project1].[C1] ASC

2 个答案:

答案 0 :(得分:3)

您可以尝试类似

的内容
context.Teams
.OrderBy(x => x.Coders
   .SelectMany(y => y.Projects)
   .SelectMany(y => y.Tasks)
   .Count());

答案 1 :(得分:2)

您可以像这样使用SelectMany

var teams = context.Teams
    .OrderBy(team =>
        team.Coders.SelectMany(coder =>
            coder.Projects.SelectMany(project => project.Tasks)).Count());
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