Question

任务是根据用户对贷款支付的最小和最大年限，贷款金额以及最小和最大百分比率的输入创建贷款计算器，并使用用户给出的递增值以及年份。期望的输出应如下所示：

原则：275000.0美元多年偿还：10 利息每月费率支付

6.25 3087.7 6.75 3157.66 7.25 3228.53

原则：275000.0美元多年还款：15 利息每月费率支付

6.25 2357.91 6.75 2433.5 7.25 2510.37

原则：275000.0美元多年偿还：20 利息每月费率支付

6.25 2010.05 6.75 2091.0 7.25 2173.53

请帮我修复错误。谢谢！

public static void main(String[] args){
            Scanner console = new Scanner (System.in);              

            System.out.println("This program computes monthly " + "mortgage payments.");
            System.out.print("Enter the loan amount:   "); 
            double loan = console.nextDouble(); 

            System.out.print("Enter the starting number of years to repay the loan:   ");
            int startingYears = console.nextInt(); 

            System.out.print("Enter the ending number of years to repay the loan:   ");
            int endingYears = console.nextInt();

            System.out.print("Enter the years increment between tables:   ");
            int incrementYears = console.nextInt();

            System.out.print("Enter the starting loan yearly interest rate, %:   ");
            double startingRate = console.nextDouble(); 

            System.out.print("Enter the ending loan yearly interest rate, %:    ");
            double endingRate = console.nextDouble(); 

            System.out.print("Enter the increment interest rate, %:   ");
            double incrementRate = console.nextDouble();            
            System.out.println();               

            System.out.println("Principle: $" + (double) loan);
            System.out.printf("Years to repay: %d\n", startingYears);
            System.out.println("-------- -------");

            double payment;             
                System.out.println("Rate\tPayment");

            for (int j = startingYears; j <= endingYears; incrementYears++) {
            for (double i = startingRate; i <= endingRate; incrementRate++){



                int n = 12 * startingYears;
                    double c = startingRate / 12.0 / 100.0;
                payment = loan * c * Math.pow(1 + c, n) / (Math.pow(1 +c, n) - 1);  

                System.out.println(i + " " + payment);
//              System.out.println(round2(startingRate) + "\t" + round2(payment));
                startingYears += incrementYears;
            }
            }


        }

        }

Answer 1

for（int j = startingYears; j＆lt; = endingYears; incrementYears ++）{

for（double i = startingRate; i＆lt; = endingRate; incrementRate ++）{

您永远不会递增计数器的值，即i和j，因此i和j的值将始终等于初始值，这些值循环将运行无限次。

增加两个计数器，使其能够分别达到终止条件，即j <= endingYears和i <= endingRate。

以下是代码段：

System.out.println("Principle: $" + (double) loan);
for (int j = startingYears; j <= endingYears; j+=incrementYears) {
    System.out.printf("Years to repay: %d\n", j);
    System.out.println("-------- -------");
    System.out.println("Rate\tPayment");
    for (double i = startingRate; i <= endingRate; i+=incrementRate){
        int n = 12 * j;
        double c = i / 12.0 / 100.0;
        double payment = loan * c * Math.pow(1 + c, n) / (Math.pow(1 + c, n) - 1); 
        System.out.println(i + "\t" + payment);
    }
    System.out.println();
}

Java Loan Calculator根据用户输入嵌套for循环

1 个答案: