Question

我的标签是以这种方式动态创建的：

ActionBar bar = getActionBar();

JSONObject jobj1 = new JSONObject(jsonObjectReceived);

    JSONArray shifts = jobj1.optJSONArray("resultObject");
    for (int m = 0; m < shifts.length(); m++) {
        bar.addTab(bar.newTab().setText("Shift " + (m + 1))
                .setTabListener(tabListener));
    }

在创建解析json_parser()对象 jsonObjectReceived 的标签后，我调用方法json，并在ListView中显示内容。

private void json_parser(String jsonObjectReceived) {
    try {
        ArrayList<String> result = new ArrayList<String>();

        JSONObject jsonRootObject = new JSONObject(jsonObjectReceived);
        JSONArray arrayOfShifts = jsonRootObject
                .getJSONArray("resultObject");
        for (int i = 0; i < arrayOfShifts.length(); i++) {
            JSONObject presentShift = arrayOfShifts.getJSONObject(i);
            String timing = presentShift.getString("shiftTimeFrom");
            TextView tv = (TextView) findViewById(R.id.ShiftTiming);
            tv.setText(timing);
            JSONArray arrayOfPatientsInPresentShift = presentShift
                    .getJSONArray("patientlist");
            if (arrayOfPatientsInPresentShift == null
                    || arrayOfPatientsInPresentShift.equals("")) {
                Toast.makeText(getApplicationContext(), "NO Patient",
                        Toast.LENGTH_LONG).show();
            }
            for (int j = 0; j < arrayOfPatientsInPresentShift.length(); j++) {
                JSONObject presentPatient = arrayOfPatientsInPresentShift
                        .getJSONObject(j);
                String Name = presentPatient.getString("patientName");
                String SL = presentPatient.getString("bookingSequence");
                String Status = presentPatient.getString("statusFlag");

                result.add(SL + " " + Name + "\n " + Status);
                Log.i("MSG", result.toString());
            }

        }
        ArrayAdapter<String> adapter = new ArrayAdapter<String>(this,
                android.R.layout.simple_list_item_1, android.R.id.text1,
                result);
        listView.setAdapter(adapter);

    } catch (Exception e) {
        e.printStackTrace();
    }

问题是，ListView显示了同一个标签中的所有项目。我知道它是因为外部的 for 循环。我想在单独的选项卡中显示来自每个外部“for”循环迭代的数据。我该怎么做？

我的JSON数据：The resultObject array contains multiple objects, and each object contains an array patientlist. patientlist contains multiple patients' details.

在尝试解决方案后Anshul Jain在答案中建议， onTabSelected（）看起来像这样：

public void onTabSelected(ActionBar.Tab tab, FragmentTransaction ft) {
            // show the given tab

            currentTabIndex = tabHost.getCurrentTab();

            json_parser(jsonString1, currentTabIndex);

        }

json_parser()方法如下所示：

private void json_parser(String jsonObjectReceived, int i) {
    try {
        ArrayList<String> result = new ArrayList<String>();

        JSONObject jsonRootObject = new JSONObject(jsonObjectReceived);
        JSONArray arrayOfShifts = jsonRootObject
                .getJSONArray("resultObject");
        // for (int i = 0; i < arrayOfShifts.length(); i++) {
        JSONObject presentShift =arrayOfShifts.getJSONObject(i);
        String timing = presentShift.getString("shiftTimeFrom");
        TextView tv = (TextView) findViewById(R.id.ShiftTiming);
        tv.setText(timing);
        JSONArray arrayOfPatientsInPresentShift = presentShift
                .getJSONArray("patientlist");

        for (int j = 0; j < arrayOfPatientsInPresentShift.length(); j++) {

            JSONObject presentPatient = arrayOfPatientsInPresentShift
                    .getJSONObject(j);
            String Name = presentPatient.getString("patientName");
            String SL = presentPatient.getString("bookingSequence");
            String Status = presentPatient.getString("statusFlag");

            result.add(SL + " " + Name + "\n " + Status);
            Log.i("MSG", result.toString());
        }
        ArrayAdapter<String> adapter = new ArrayAdapter<String>(this,
                android.R.layout.simple_list_item_1, android.R.id.text1,
                result);
        listView.setAdapter(adapter);

    } catch (Exception e) {
        e.printStackTrace();
    }

但是app崩溃了。

Answer 1

您的活动应实施ActionBar.TabListener，其中包含以下方法。从onTabSelected()方法，使用正确的json调用jsonParser()方法。

  @Override
public void onTabSelected(ActionBar.Tab tab, FragmentTransaction fragmentTransaction) {
    //Gets called when  a tab is selected


}

@Override
public void onTabUnselected(ActionBar.Tab tab, FragmentTransaction fragmentTransaction) {

}

@Override
public void onTabReselected(ActionBar.Tab tab, FragmentTransaction fragmentTransaction) {

}

Answer 2

很抱歉打扰你们，得到解决方案。事实证明我一直在使用错误的方法来获取当前选项卡的索引。我使用getCurrentTab()和TabHost对象来调用它。应该使用getPosition()代替。

public void onTabSelected(ActionBar.Tab tab, FragmentTransaction ft) {
            // show the given tab

            try {
                json_parser(jsonString1, tab.getPosition());
            } catch (Exception e) {
            }
        }

如何更改动态创建的选项卡更改活动的内容？

2 个答案: