Question

我正在创建一个表格，用于将照片上传到比赛中。我在桌面版本中没有任何问题，但智能手机存在的问题是每张照片都被加载为＆＃34; image.jpeg＆＃34;或＆＃34; image.jpg＆＃34;从而阻止上传下一个，因为它检测到同名图像。我怎样才能克服这个问题？这是我的代码：

<?php
    $target_dir = "uploads/";
    $target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
    $uploadOk = 1;
    $imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);

    // Check if image file is a actual image or fake image
    if(isset($_POST["submit"])) {
        $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
        if($check !== false) {
            echo "File is an image - " . $check["mime"] . ".";
            $uploadOk = 1;
        } else {
            echo "Il file selezionato non è un'immagine. ";
            $uploadOk = 0;
        }
    }
    // Check if file already exists
    if (file_exists($target_file)) {
        echo "Spiacente, una foto con lo stesso nome è già stata inviata. ";
        $uploadOk = 0;
    }
    // Check file size 500kb
    if ($_FILES["fileToUpload"]["size"] > 2000000) {
        echo "Spiacente, le dimesioni della foto superano il limite consentito. ";
        $uploadOk = 0;
    }
    // Allow certain file formats
    if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
    && $imageFileType != "gif" ) {
        echo "Spiacente, i formati consentiti sono jpg e png. ";
        $uploadOk = 0;
    }
    // Check if $uploadOk is set to 0 by an error
    if ($uploadOk == 0) {
        echo "Spiacente la tua foto non è stata inviata. ";
    // if everything is ok, try to upload file
    } else {
        if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
            @mail($email_to, $email_subject, $email_message, $headers); 
            echo "Messaggio Inviato. La tua foto ". basename( $_FILES["fileToUpload"]["name"]). " è stata inviata con successo. ";
        } else {
            echo "Spiacente, si è verificato un errore nel caricamento della tua foto. ";
        }
    }
    ?>

Answer 1

检查文件是否存在，如果存在，则创建一个附加时间的新文件名（或类似的东西），然后移动上传的文件。

下面给出了一个样本，你应该修改它以满足你的需要

SELECT pl.id, pl.location_id, pl.mois, pl.annee, pl.loyer_paye, 
        l.loyer, l.charges, l.locataire_id, laire.nom, laire.prenom,
       l.chambre_id, c.numero, c.etage, c.maison_id, m.titre_crm 
FROM
(
    SELECT spl.id, spl.location_id, spl.mois, spl.annee, spl.loyer_paye
    FROM locations sl 
    LEFT OUTER JOIN
    (
        SELECT id, location_id, mois, annee, loyer_paye
        FROM paiement_loyer 
        UNION 
        SELECT 9999, usl.id, (MONTH(NOW())-1), YEAR(NOW()), 0
        FROM locations usl 
        LEFT OUTER JOIN paiement_loyer pl1
        ON usl.id = pl1.location_id 
        WHERE pl1.location_id IS NULL
        SELECT 9999, usl.id, (MONTH(NOW())-1), YEAR(NOW()), 0
        FROM locations usl 
        LEFT OUTER JOIN paiement_loyer pl2
        ON usl.id = pl1.location_id 
        AND pl2.annee = YEAR(NOW()) 
        AND pl2.mois=(MONTH(NOW())-1)
        WHERE pl2.location_id IS NULL
    ) spl ON sl.id = spl.location_id
    WHERE CURDATE() BETWEEN sl.date_debut AND sl.date_fin
) pl
JOIN locations l ON pl.location_id = l.id
JOIN locataires laire ON l.locataire_id = laire.id
JOIN chambres c ON l.chambre_id = c.id
JOIN maisons m ON c.maison_id = m.id
ORDER BY TRIM(UPPER(m.titre_crm)), c.numero, pl.annee, pl.mois

跳过＆＃34;检查文件是否已经存在＆＃34;

1 个答案: