发布请求始终由可选文本包装

时间:2016-02-04 09:34:12

标签: php xcode swift http-post optional

我有一个非常类似的问题,例如Why the http post request body always wrapped by Optional text in the Swift app 但我无法将此线程的解决方案应用于我的代码,因为我没有request.setValue。 有谁知道我需要做什么来摆脱可选? 我的代码:

 @IBAction func LoginButtonTapped(sender: UIButton) {

    let username = UsernameTextField.text
    let password = PasswordTextField.text

    if(username!.isEmpty || password!.isEmpty) {return; }



    let request = NSMutableURLRequest (URL: NSURL(string: "http://myip/loginregister.php")!)
    request.HTTPMethod = "POST"
    let postString = "username=\(username)&password=\(password)"
    request.HTTPBody = postString.dataUsingEncoding(NSUTF8StringEncoding)
    let task = NSURLSession.sharedSession().dataTaskWithRequest(request) { data, response, error in
        guard error == nil && data != nil else {
            // check for fundamental networking error
            print("error=\(error)")
            return
        }

        let data = postString.dataUsingEncoding(NSUTF8StringEncoding, allowLossyConversion: false)!



        do {
            if let json = try NSJSONSerialization.JSONObjectWithData(data, options: []) as? NSDictionary {
                let success = json["success"] as? Int                                  // Okay, the `json` is here, let's get the value for 'success' out of it
                print("Success: \(success)")
            } else {
                let jsonStr = NSString(data: data, encoding: NSUTF8StringEncoding)    // No error thrown, but not NSDictionary
                print("Error could not parse JSON: \(jsonStr)")
            }
        } catch let parseError {
            print(parseError)                                                          // Log the error thrown by `JSONObjectWithData`
            let jsonStr = NSString(data: data, encoding: NSUTF8StringEncoding)
            print("Error could not parse JSON: '\(jsonStr)'")
        }
    }

    task.resume()

1 个答案:

答案 0 :(得分:1)

首先从UITextField获取文本时必须展开值,因为text的{​​{1}}属性允许UITextField

nil

解释更多

当您打开UITextField的let username = UsernameTextField.text! let password = PasswordTextField.text! 时,textusername将是password变量。 代码比较空应该是:

not nil

如果你没有打开,当你使用这个if(username.isEmpty || password.isEmpty) {return } 时,你会尝试将"\(username)"能力对象转换为字符串,因此字符串结果将附加一个“可选”文本。 / p>

解决Content-Type for request

的问题

将此行粘贴到您的代码中。我不相信你没有nil方法。

setValue
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