Question

我正在尝试从表单中单击哪个按钮。我在表单中有3个按钮就是我的视图：

<div class="form-actions">
  <button type="submit" name="submit" class="btn green"><i class="fa fa-check"></i> Submit</button>
  <button type="submit" name="draft" class="btn btn-warning"><i class="fa fa-paper-plane-o"></i> Draft</button>
  <button type="submit" name="Trash" class="btn red"><i class="fa fa-trash-o"></i> Trash</button>
</div>

以下是我在我的控制器上检查的方法：

  if(Button::get('submit')) {
  $request['status'] = 1;
}
elseif(Input::has('draft')) {
  $request['status'] = 2;
} else {
  return "something else"; //i am ending us with this all the time.

}

我总是以something else 结尾。当我做return $request->except('_token');我得到这个：

{
  "pagename": "asdfasdf",
  "pagecontent": "<p>asdfasdf<\/p>\r\n",
  "displayfrom": "2016-02-04 00:00:00",
  "submit": "",
  "metatitle": "",
  "metakeywords": "",
  "metadescription": "",
  "user": 11,
  "active": 1
}

我不知道为什么它没有得到<button type="submit">的价值。

任何建议都会有所帮助。谢谢！

Answer 1

在提交按钮value="submit"

中添加此项

<button type="submit" value="submit" name="submit" class="btn green">
<button type="submit" value="draft" name="draft" class="btn btn-warning">

检查是否在Laravel

1 个答案: