Question

我有这个代码显示两个权力：

print ("How many powers of two would you like to see?")
number=int(input())
values=[2]
count=1
while count <=  number:
    length=len(values)
    index=length-1
    number=values[index]*2
    values.append(number)
    count=count+1 
print (values)

我的代码正在更新count的值，但它不会突破while循环。

Answer 1

您在每个while循环中比较count <= number，但在循环内比number增加count。请勿触摸循环中的number，如下所示：

print("How many powers of two would you like to see?")
number = int(input())

values = [2]
count = 1
while count <= number:
    length = len(values)
    index = length - 1
    number_tmp = values[index]*2
    values.append(number_tmp)
    count += 1    
print(values)

但是更加pythonic的方式是：

print("How many powers of two would you like to see?")
number = int(input())

values = [2**(n+1) for n in range(number)]

print(values)

Answer 2

如果您在第40次迭代后查看数字的值，count = 40但是

number = 2199023255552

在第1000次迭代之后，count = 1000但是

number = 21430172143725346418968500981200036211228096234110672148875007767407021022498722449863967576313917162551893458351062936503742905713846280871969155149397149607869135549648461970842149210124742283755908364306092949967163882534797535118331087892154125829142392955373084335320859663305248773674411336138752

因此，计数永远不会超过number，循环永远不会中断。您可以通过不更改循环内的number值来更改此值。

为什么我的代码没有突破我的while循环？

2 个答案: