Question

<html>
<head><title> Inpatient Search </title><head>
<body>

<h1> Inpatient Search </h1>


<?php
$wardnumber = $_POST['wardnumber'];


$conn = mysqli_connect("127.0.0.1","root","root","");
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

if ($q1 = mysqli_query($conn,"select s.Inpatient_id, s.Ward_number,c.Room_number,c.Floor_number,c.Class 
        from joseph.ward_stay_1501003f s, joseph.ward_1501003f c 
        where s.Ward_number = c.Ward_number and s.Ward_number='$wardnumber'")) {

    print "<table border=1>";

    print "<TR><TH>Inpatient id</TH><TH>Ward number</TH><TH>Room number</TH><TH>Floor number</TH><TH>Class</TH></TR>";

    while ($r1 = mysqli_fetch_row($q1)) {
        for ($k=0; $k<count($r1); $k++){    
            print htmlspecialchars($r1[$k]). " : "; 
        }   
        print "<BR>";   
    };

} else {
  printf("Errormessage: %s\n", mysqli_error($conn));
}

mysqli_close($conn);

?>
</body>
</html>

我有一个有序的输出。如何修复它以使标题表位于数据之上？

Answer 1

while ($r1 = mysqli_fetch_row($q1)) {
  print "<tr>"; //you have to initiate a table row
  for ($k=0; $k<count($r1); $k++){    
    print "<td>"; //AND table cells.
    print htmlspecialchars($r1[$k]). " : ";   
    print "</td>";// which to close is optional, but clean
 }    
 print "</tr>";    //but BR is for text, not for tables.
};

当您将数据写入表格时，您也必须使用表格结构。

编辑：哦，不要忘记用

关闭你的桌子

print "</table>";

</td>和</tr>标记是可选的，</table>不是。

PHP奇怪的输出

1 个答案: