Question

我有以下json，

{   
    "method":"login", 
    "data":{  
        "username":"abc", 
        "password":"123" 
    } 
}

我正在使用以下代码来解析它，

NSString* loginMethod= json[@"method"];
NSString* credentials= json[@"data"];
NSLog(@"credentials %@",credentials);

我能够获取密钥数据的值，但我无法获得用户名和密码的值。如何获得这些价值观？

Answer 1

变化

NSString* credentials= json[@"data"];

到

NSDictionary* credentials= json[@"data"];

然后

NSString *username = credentials[@"username"];

Answer 2

您可以按credentials[@"username"]和credentials[@"password"]获取这些值。

Answer 3

喜欢

它会像嵌套Dictionry

那样失真

NSString* loginMethod= json[@"method"]; // this is correct

NSString* username= json[@"data"][@"username"];
NSString* password= json[@"data"][@"password"];

选择-2

 NSString* loginMethod= json[@"method"]; 

// This isNested Dictionary so Do like
NSDictionary* temp= json[@"data"];
NSString *username = temp[@"username"];
NSString * password = temp[@"password"];

Answer 4

如果json处于respose数据中，那么

NSDictionary *jsonDic = [NSJSONSerialization JSONObjectWithData:request.responseData options:kNilOptions error:&err];

如果json是字符串，那么

NSDictionary *jsonDic = [NSJSONSerialization JSONObjectWithData:[str dataUsingEncoding:NSUTF8StringEncoding]; options:kNilOptions error:&err];


NSString* loginMethod= [jsonDic objectForKey:@"method"];

NSString* usename= [[jsonDic objectForKey:@"data"]objectForKey:@"username"];
NSString* password= [[jsonDic objectForKey:@"data"]objectForKey:@"password"];

如何使用Objective c解析iOS中的jsonstring？

4 个答案: