Question

所以，我试图创建一个帐户确认，但它没有工作。

这是登录页面，它应该检查帐户何时被激活，但即使数据已在数据库中确认，它始终显示它未被激活，因此它始终显示未激活的消息。

if(isset($_POST['login_button']))
{
$userName = $_POST['username']; 
$userPass = $_POST['password']; 

$hashedPass = hash('whirlpool', $userPass);
$query = "SELECT Ime FROM Igraci WHERE Ime = '$userName' AND Lozinka = '$hashedPass'";
$stmt = mysqli_prepare($con, $query) or die(mysqli_error($con));
mysqli_stmt_bind_param($stmt, "ss", $userName, $hashedPass);
mysqli_stmt_execute($stmt);
$result = mysqli_stmt_get_result($stmt);
$row = mysqli_fetch_array($result);

while($conf = mysqli_fetch_assoc(query))
{
    $aktiviran = $conf['Confirmed'];
}

if($row)
{

    if($aktiviran == 1)
    {
        $session = md5($userName.$hashedPass);
        mysqli_query($con, "UPDATE Igraci SET session = '$session' WHERE Ime = '$userName' AND Lozinka = '$hashedPass'");
        setcookie("username", $_POST['username'], time()+3600*24);
        setcookie("authorization","ok");
        header( "Location:welcome.php");
        exit();
    }
    else
    {
        echo '
                        <div class="transbox" position = "center">

            <center><p>Ovaj racun nije aktiviran, molimo da ga aktivirate.</p>
            <p>Ukoliko niste primili email proverite junk folder ili ponovo zatrazite aktivaciju racuna.</p>
            </center>

            </div>
        ';

    }
}

Answer 1

试试这样：

if($row) {
     if($row[number of the column 'Confirmed']==1) {
         // do the stuff
     } else {
         // do the other stuff
     }
}

这样你就不会需要while（）和fetch_assoc（）（返回null）

确认帐户无效

1 个答案: