Question

如何转换我的数组：

["Collaboration", "Personal", "Services", "Financial", "Enginerring", "Infrastructure", "Application", "null"]

到对象数组：

["title": "Collaboration", "title":"Personal", "title":"Services", "title":"Financial", "title":"Enginerring", "title":"Infrastructure", "title":"Application", "title":"null"]

我做了类似的事情：

var mainmenu = [];
for(var i=0; menus.length > i;i++){
    mainmenu[i] = "{title:"+menus[i]+"}";   
}

但我得到了：

["{title:Collaboration}", "{title:Personal}", "{title:Services}", "{title:Financial}", "{title:Enginerring}", "{title:Infrastructure}", "{title:Application}"]

那么如果没有双引号怎么可能呢？

Answer 1

尝试使用.map

var data = ["Collaboration", "Personal", "Services", "Financial", "Enginerring", "Infrastructure", "Application", "null"];
var result = data.map(function (title) {
  return { title: title };
}) 

console.log(result);

在您使用String代替Object的代码问题中，请移除"

  mainmenu[i] = { title:  menus[i] };
               ^^^    ^^ ^^      ^^^

Answer 2

那是因为你正在创建字符串而不是实际的对象。创建这样的对象：

mainmenu[i] = {
    title: menus[i]
};

Answer 3

es6

    public class DebuggerPagerAdapter extends FragmentPagerAdapter  {

  public DebuggerPagerAdapter(FragmentManager fm) {
    super(fm);
  }

  @Override
  public Fragment getItem(int position) {

    switch (position){
      case 0:
        return MemoryFragment.getInstance();
      case 1:
        return NetworkFragment.getInstance();
      case 2:
        return CpuFragment.getInstance();
    }
    return null;
  }

  @Override
  public int getCount() {
    return 3;
  }
}

ES5

var data = ["Collaboration", "Personal", "Services", "Financial","Enginerring", "Infrastructure", "Application", "null"];
data.map(function(title) {
    return {
        title: title
    }
})

Answer 4

这是一个可以使用Array.from()的好例子：

Array.from（）方法从中创建一个新的Array实例   类似数组或可迭代的对象。

在ES6中，类语法允许内置和子类的子类化   用户定义的类;因此，类侧静态方法如   Array.from是“继承”由Array的子类创建并创建新的   子类的实例，而不是Array。

var data = ["Collaboration", "Personal", "Services", "Financial", "Enginerring", "Infrastructure", "Application", "null"];
console.log(Array.from(data, x => ({title : x})));

将数组转换为对象数组

4 个答案: