Question

我的问题是你如何连接para1和para2，并在PHP中显示web1数组中每个数据的url中的图像？

这是我想要的一个例子。

来自网址：www.example.com/jferf0923i092eijodsojs

请记住，这些网址只是我想要实现的一个例子。

{"Web 1": {
      "url1": {
        "para1": "www.example.com",
        "para2": /jferf0923i092eijodsojs,
      },
      "url2": { 
        "para1": "www.example.com",
        "para2": asjdoisadj829332oijd,
      },
      "url3": {
        "para1": "www.example.com",
        "para2": assasdijoj21389445,
      }
      }}

感谢您的帮助！干杯

Answer 1

我认为这大致是你正在寻找的，至少它应该给你一个开始：

<?php
$catalog = [
    "Web 1" => [
        "url1" => [
            "para1" => "www.example.com",
            "para2" => "jferf0923i092eijodsojs",
        ],
        "url2" => [
            "para1" => "www.example.com",
            "para2" => "asjdoisadj829332oijd",
        ],
        "url3" => [
            "para1" => "www.example.com",
            "para2" => "assasdijoj21389445",
        ]
    ]
];

foreach ($catalog as $entry) {
    foreach ($entry as $url) {
        $imageUrl = sprintf('https://%s/%s', $url['para1'], $url['para2']);
        echo '<img src="' . $imageUrl . '">'."\n";
    }
}

输出是有效的html，并且在html页面中使用时应该可视化图像：

<img src="https://www.example.com/jferf0923i092eijodsojs">
<img src="https://www.example.com/asjdoisadj829332oijd">
<img src="https://www.example.com/assasdijoj21389445">

连接URL并在URL PHP中显示图像

1 个答案: